Math Problem Statement

Find the mass of the solid bounded by the the graphs of  y  =  6x2,  y  =  8,  z  =  0,  and  z  =  7, in the first octant, if the density at a point P is equal to 5 times the distance to the yz-plane.

Solution

To find the mass of the solid bounded by the given surfaces and with the given density function, we need to set up and evaluate a triple integral.

Step 1: Determine the Volume Boundaries

The solid is bounded by the surfaces:

  1. y=6x2y = 6x^2
  2. y=8y = 8
  3. z=0z = 0
  4. z=7z = 7

The region is in the first octant where x0x \geq 0, y0y \geq 0, and z0z \geq 0.

Step 2: Density Function

The density function at a point P(x,y,z)P(x, y, z) is given by ρ=5x\rho = 5x, because the distance to the yz-plane is xx.

Step 3: Setting Up the Triple Integral

The mass MM of the solid is given by: M=VρdVM = \iiint_V \rho \, dV

Since the density ρ=5x\rho = 5x, we have: M=V5xdVM = \iiint_V 5x \, dV

Step 4: Limits of Integration

  • xx ranges from 00 to y6\sqrt{\frac{y}{6}} because y=6x2y = 6x^2.
  • yy ranges from 00 to 88.
  • zz ranges from 00 to 77.

Therefore, the triple integral becomes: M=080y6075xdzdxdyM = \int_{0}^{8} \int_{0}^{\sqrt{\frac{y}{6}}} \int_{0}^{7} 5x \, dz \, dx \, dy

Step 5: Evaluating the Integral

First, integrate with respect to zz: 075xdz=5x[z]07=5x(70)=35x\int_{0}^{7} 5x \, dz = 5x \left[ z \right]_{0}^{7} = 5x(7 - 0) = 35x

Now, substitute this result into the remaining integral: M=080y635xdxdyM = \int_{0}^{8} \int_{0}^{\sqrt{\frac{y}{6}}} 35x \, dx \, dy

Next, integrate with respect to xx: 0y635xdx=35[x22]0y6=35((y6)220)=35(y/62)=35y12\int_{0}^{\sqrt{\frac{y}{6}}} 35x \, dx = 35 \left[ \frac{x^2}{2} \right]_{0}^{\sqrt{\frac{y}{6}}} = 35 \left( \frac{(\sqrt{\frac{y}{6}})^2}{2} - 0 \right) = 35 \left( \frac{y/6}{2} \right) = \frac{35y}{12}

Finally, integrate with respect to yy: M=0835y12dy=351208ydyM = \int_{0}^{8} \frac{35y}{12} \, dy = \frac{35}{12} \int_{0}^{8} y \, dy 3512[y22]08=3512(8220)=3512(642)=3512×32=112012=93.333\frac{35}{12} \left[ \frac{y^2}{2} \right]_{0}^{8} = \frac{35}{12} \left( \frac{8^2}{2} - 0 \right) = \frac{35}{12} \left( \frac{64}{2} \right) = \frac{35}{12} \times 32 = \frac{1120}{12} = 93.33\overline{3}

Final Answer

The mass of the solid is: M=93.3units of massM = 93.\overline{3} \, \text{units of mass}

Do you want any details or have any questions?

Here are some related questions:

  1. How do you set up triple integrals for finding volumes?
  2. What are the common methods for integrating functions of several variables?
  3. How do you interpret the density function in physical problems?
  4. Can you describe the method of slicing to find volumes of solids?
  5. What are the applications of triple integrals in real-world problems?
  6. How do you determine the limits of integration in cylindrical coordinates?
  7. What are the differences between Cartesian, cylindrical, and spherical coordinate systems?
  8. How do you handle integrals with variable limits?

Tip: When solving problems involving density functions and volumes, visualize the region and carefully determine the bounds of integration to set up the correct integral.

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Math Problem Analysis

Mathematical Concepts

Triple Integrals
Density Functions
Volume Calculation

Formulas

Triple integral setup

Theorems

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Suitable Grade Level

Advanced Mathematics