Calculate the mass, in grams, of a single tellurium atom ( mTe
  = 127.60  amu
  ).
Express your answer using four significant figures.

To calculate the mass of a single tellurium (Te) atom in grams, we need to use the conversion factor between atomic mass units (amu) and grams. Specifically, 1 atomic mass unit (amu) is equal to \( 1.66054 \times 10^{-24} \) grams.

Given the atomic mass of tellurium (\( m_{Te} \)) is 127.60 amu, the mass in grams can be calculated as follows:

\[
\text{Mass of one Te atom} = 127.60 \, \text{amu} \times 1.66054 \times 10^{-24} \, \text{g/amu}
\]

Let's compute the result.

\[
\text{Mass of one Te atom} = 127.60 \times 1.66054 \times 10^{-24} = 2.1182 \times 10^{-22} \, \text{g}
\]

Thus, the mass of a single tellurium atom is \( 2.118 \times 10^{-22} \) grams (rounded to four significant figures).

Would you like to discuss the details or ask further questions?

Here are some related questions:
1. What is the atomic mass unit (amu) and its significance?
2. How do you calculate the number of atoms in a sample of tellurium?
3. What role does Avogadro’s number play in atomic mass conversions?
4. How do you calculate the molar mass of an element from atomic mass?
5. What is the difference between atomic mass and molar mass?

**Tip:** Always keep track of significant figures in calculations to ensure accuracy, especially in scientific contexts!

Calculate the mass, in grams, of a single tellurium atom (mTe = 127.60 amu). Express your answer using four significant figures.

Learn how to calculate the mass of a single tellurium atom, given its atomic mass of 127.60 amu. This solution walks through the conversion from atomic mass units to grams using the conversion factor (1 amu = 1.66054 × 10^-24 g). Suitable for high school chemistry students in Grades 10-12.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation