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The problem provided involves determining the angle at which a beam of light exits a glass interface and enters water after initially striking the glass at an angle of 43.5° with respect to the normal. Let's analyze the information provided and solve it using Snell's Law.

### Solution Steps:

1. **Apply Snell's Law at the air-glass interface**:
   \[
   n_{\text{air}} \sin(\theta_{\text{air}}) = n_{\text{glass}} \sin(\theta_{\text{glass}})
   \]
   where:
   - \( n_{\text{air}} = 1 \) (index of refraction of air),
   - \( n_{\text{glass}} = 1.56 \) (index of refraction of the glass),
   - \( \theta_{\text{air}} = 43.5^\circ \) (incident angle in air).

   Rearranging to solve for \( \theta_{\text{glass}} \):
   \[
   \sin(\theta_{\text{glass}}) = \frac{n_{\text{air}} \sin(\theta_{\text{air}})}{n_{\text{glass}}}
   \]

2. **Calculate \( \theta_{\text{glass}} \)** using the values provided.

3. **Apply Snell's Law at the glass-water interface**:
   After finding \( \theta_{\text{glass}} \), we can find the refraction angle as the light passes from glass into water:
   \[
   n_{\text{glass}} \sin(\theta_{\text{glass}}) = n_{\text{water}} \sin(\theta_{\text{water}})
   \]
   where:
   - \( n_{\text{water}} \approx 1.33 \).

4. **Calculate \( \theta_{\text{water}} \)**, the angle at which the light enters the water.

Would you like to proceed with the calculation, or need further clarification on any step? 

### Related Questions:

1. What happens to the light angle if the refractive index of water changes?
2. How does the angle change if the light enters at a different initial angle?
3. How would we approach this if the glass was curved instead of flat?
4. How does wavelength affect refraction in different materials?
5. Can Snell's Law apply to non-visible wavelengths like infrared?

**Tip:** Always double-check the refractive indices when dealing with different materials to ensure accuracy.

An aquarium filled with water has flat glass sides whose index of refraction is 1.56. A beam of light from outside the aquarium strikes the glass at a 43.5° angle to the perpendicular. At what angle does each beam leave the prism (give angle with normal to the face)?

Determine the angle at which a beam of light exits an aquarium's glass side and enters water using Snell's Law. This problem involves calculating refraction angles given an incident angle of 43.5° and indexes of refraction for glass and water. Suitable for high school students in Grades 10-12 studying refraction and Snell's Law.

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