Let the breadth of the pool be denoted by $b$.

According to the problem, the length $l$ is 2 meters more than twice the breadth. Therefore, we can express the length as: $l = 2b + 2$

We are also given that the perimeter of the rectangular pool is 154 meters. The formula for the perimeter $P$ of a rectangle is: $P = 2(l + b)$ Substituting the values: $154 = 2(l + b)$

Now, substitute the expression for $l$ into the perimeter equation: $154 = 2((2b + 2) + b)$ Simplifying: $154 = 2(3b + 2)$ Divide both sides by 2: $77 = 3b + 2$ Subtract 2 from both sides: $75 = 3b$ Divide by 3: $b = 25$

Now that we have the breadth, substitute it back into the expression for the length: $l = 2b + 2 = 2(25) + 2 = 50 + 2 = 52$

Thus, the dimensions of the pool are:

• Length: 52 meters
• Breadth: 25 meters

Would you like further details or have any questions?

Here are five related questions to further your understanding:

1. What would the perimeter be if both the length and breadth were increased by 10 meters?
2. How would the dimensions change if the perimeter was reduced to 100 meters?
3. Can you derive a formula to calculate the dimensions for any given perimeter and similar length-breadth relationship?
4. What would the area of the pool be, given the length and breadth calculated?
5. How would the perimeter formula change if the shape were a square instead of a rectangle?

Tip: When solving problems involving geometric figures, translating words into equations is key to finding relationships between dimensions.