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The problem states that equal amounts are invested in three accounts with interest rates of 4%, 6%, and 11.5% annually. The combined interest income for one year is $1,053.50. We need to determine how much is invested in each account.

Let the amount invested in each account be denoted by $ x $. Since the same amount is invested in each of the three accounts, the total interest from all three accounts is:

\[
\text{Total Interest} = 0.04x + 0.06x + 0.115x
\]

The combined interest from all three accounts is given as $1,053.50. Therefore, the equation becomes:

\[
0.04x + 0.06x + 0.115x = 1053.50
\]

Now, we can simplify and solve for $ x $. Let's compute.The amount invested in each account is $4,900.

Would you like more details or have any questions?

Here are 5 related questions to expand your understanding:

1. How much interest does each account generate individually?
2. What would happen if the interest rates were different for each account?
3. How much total principal is invested across all three accounts?
4. How would the answer change if the combined interest income were $1,200 instead?
5. How long would it take for the total investment to double if the same rates apply?

**Tip:** When dealing with percentages, always convert them to decimal form (e.g., 4% becomes 0.04) before performing calculations.

Equal amounts are invested in each of three accounts paying 4%, 6%, and 11.5% annually. If one year's combined interest income is $1,053.50, how much is invested in each account?

Learn how to calculate the equal investment amounts for three accounts paying different interest rates (4%, 6%, and 11.5%) with a combined interest income of $1,053.50. A practical application of algebra and percentages for high school students in Grades 10-12.

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