Math Problem Statement

If $5000 earns $6000 simple interest in 12 years, find the interest rate.

Solution

To solve the problem of finding the interest rate, we can use the simple interest formula:

Simple Interest (SI)=P×R×T100\text{Simple Interest (SI)} = \frac{P \times R \times T}{100}

Where:

  • PP is the principal amount (initial amount), which is $5000.
  • RR is the interest rate (what we need to find).
  • TT is the time in years, which is 12 years.
  • SI is the simple interest, which is $6000.

Given:

  • P=5000P = 5000 dollars
  • T=12T = 12 years
  • SI=6000\text{SI} = 6000 dollars

We substitute the values into the formula:

6000=5000×R×121006000 = \frac{5000 \times R \times 12}{100}

Now, solve for RR:

6000=5000×R×121006000 = \frac{5000 \times R \times 12}{100}

Multiply both sides by 100 to eliminate the fraction:

600000=5000×R×12600000 = 5000 \times R \times 12

Now, divide both sides by 5000×125000 \times 12:

R=6000005000×12R = \frac{600000}{5000 \times 12}

Simplifying:

R=60000060000=10%R = \frac{600000}{60000} = 10\%

So, the interest rate is 10%.

Would you like more details or have any questions?


Here are 5 related questions for further practice:

  1. If $4000 earns $800 simple interest in 4 years, what is the interest rate?
  2. Find the time required for $3000 to earn $900 as simple interest at a rate of 5%.
  3. Calculate the simple interest earned by $7000 in 5 years at a rate of 8%.
  4. If $2500 is invested at a 12% interest rate, how much interest will it earn in 3 years?
  5. How much time will it take for $6000 to double itself at a 6% simple interest rate?

Tip: Always ensure the units (e.g., years for time, percentage for interest rate) are consistent when applying formulas.