The weatherman on a local station reported that at the end of August, central Indiana was two and a fourth inches below the average precipitation for the year so far.

How many inches above average, per month, would central Indiana need to receive to be back at the normal average by the end of the year?

Answer in fraction form.

To solve this problem, we first need to determine the number of months remaining in the year after August. 

Since August is the 8th month of the year, there are 4 months remaining (September, October, November, and December).

Now, the total deficit in precipitation is \(2 \frac{1}{4}\) inches. In fraction form, this is:

\[
2 \frac{1}{4} = \frac{9}{4} \text{ inches}
\]

Next, we need to find out how many inches above average, per month, are needed to make up this deficit over the remaining 4 months. We can do this by dividing the total deficit by the number of months remaining:

\[
\text{Inches per month} = \frac{\frac{9}{4}}{4} = \frac{9}{4} \times \frac{1}{4} = \frac{9}{16} \text{ inches}
\]

So, central Indiana would need to receive **\(\frac{9}{16}\)** inches above average per month to be back at the normal average by the end of the year.

Would you like more details or have any questions?

Here are some related questions you might find interesting:

1. If the deficit was \(3 \frac{1}{2}\) inches, how much above average per month would be needed?
2. What is the equivalent decimal value of \(\frac{9}{16}\) inches?
3. How much total precipitation would be needed over the next 4 months to reach the average?
4. If September has already received \( \frac{5}{16} \) inches above average, how much is still needed per month?
5. What would be the deficit at the end of October if only \( \frac{1}{4} \) inches above average were received in September and October?

**Tip:** When dealing with fractional amounts, always reduce them to their simplest form for clarity.

Discover how many inches above average per month Central Indiana needs to receive to make up a precipitation deficit of 2 1/4 inches by the end of the year. This problem involves fractions and basic arithmetic calculations. Suitable for students in Grades 4-6.

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