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The question here involves calculating the gravitational force of attraction between the Earth and the Sun using Newton's law of universal gravitation.

### Given Data:
1. Gravitational constant, \( G = 6.7 \times 10^{-11} \, \text{Nm}^2/\text{kg}^2 \)
2. Mass of the Earth, \( M_{\text{Earth}} = 6.0 \times 10^{24} \, \text{kg} \)
3. Mass of the Sun, \( M_{\text{Sun}} = 2.0 \times 10^{30} \, \text{kg} \)
4. Distance between Earth and Sun, \( r = 1.5 \times 10^{11} \, \text{m} \)

### Formula:
The gravitational force \( F \) between two masses \( M_1 \) and \( M_2 \) separated by a distance \( r \) is given by:

\[
F = \frac{G \cdot M_1 \cdot M_2}{r^2}
\]

### Substitution:
1. Substitute \( G = 6.7 \times 10^{-11} \),
2. \( M_1 = 6.0 \times 10^{24} \) (mass of Earth),
3. \( M_2 = 2.0 \times 10^{30} \) (mass of Sun),
4. \( r = 1.5 \times 10^{11} \).

\[
F = \frac{(6.7 \times 10^{-11}) \times (6.0 \times 10^{24}) \times (2.0 \times 10^{30})}{(1.5 \times 10^{11})^2}
\]

Let's compute each step:

1. Multiply the masses and gravitational constant:
   \[
   6.7 \times 10^{-11} \times 6.0 \times 10^{24} \times 2.0 \times 10^{30} = 8.04 \times 10^{44}
   \]

2. Square the distance:
   \[
   (1.5 \times 10^{11})^2 = 2.25 \times 10^{22}
   \]

3. Divide the result of the product by the squared distance:
   \[
   F = \frac{8.04 \times 10^{44}}{2.25 \times 10^{22}} = 3.58 \times 10^{22} \, \text{N}
   \]

### Final Answer:
The gravitational force of attraction between the Earth and the Sun is approximately:

\[
F \approx 3.58 \times 10^{22} \, \text{N}
\]

Would you like a breakdown of each calculation step or have any other questions?

### Related Questions:
1. How does the gravitational force change if the distance between the Earth and the Sun increases?
2. What would happen to the force if the mass of the Earth doubled?
3. How would the force calculation change if a different celestial body was involved?
4. Can the gravitational force be shielded or blocked by any material?
5. How is this gravitational force responsible for keeping Earth in orbit?

### Tip:
Always make sure units are consistent when using formulas in physics; mismatched units can lead to incorrect results.

Calculate the force of attraction between the Earth and the Sun, given:
- Gravitational constant (G) = 6.7 × 10^(-11) Nm²/kg²
- Radius of Earth = 6.4 × 10^6 m
- Mass of Earth = 6.0 × 10^24 kg
- Mass of Sun = 2.0 × 10^30 kg
- Distance between Earth and Sun = 1.5 × 10^11 m.

Learn how to calculate the gravitational force of attraction between Earth and the Sun using Newton's Law of Universal Gravitation. This problem uses data for Earth's mass, Sun's mass, and the distance between Earth and the Sun. Suitable for high school physics students in Grades 10-12.

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