The graph of the continuous function f consists of three line segments and a semicircle centered at point (5, 1), as shown above. If  is an antiderivative of f(x) such that F(0)= 2, what is the value of F(9)?

To find the value of \( F(9) \), we need to understand the relationship between \( F(x) \) and \( f(x) \). Since \( F(x) \) is an antiderivative of \( f(x) \), we have:

\[
F(x) = \int f(x) \, dx + C
\]

Given that \( F(0) = 2 \), the constant \( C \) is 2. Our goal is to find the value of \( F(9) \), which depends on the integral of \( f(x) \) from 0 to 9:

\[
F(9) = F(0) + \int_{0}^{9} f(x) \, dx
\]

So, we need to calculate the definite integral \( \int_{0}^{9} f(x) \, dx \) by analyzing the areas under the graph of \( f(x) \). 

### Analyzing the Graph of \( f(x) \)

Since \( f(x) \) consists of line segments and a semicircle, we'll compute the area under each segment between \( x = 0 \) and \( x = 9 \). Let’s assume that the graph is split into these segments:

1. **Segment from \( x = 0 \) to \( x = a \)**
2. **Segment from \( x = a \) to \( x = b \)**
3. **Segment from \( x = b \) to \( x = c \)**
4. **Semicircle from \( x = c \) to \( x = d \)**
5. **Segment from \( x = d \) to \( x = 9 \)**

Let’s denote the x-coordinates for these divisions based on the structure mentioned.

### Calculating the Integral

Let's analyze these segments individually:

- **Area of Line Segments:** We need the exact coordinates for precise calculation. Typically, the area under line segments can be calculated using the trapezoidal rule or by directly computing the area of triangles and rectangles formed by the segments.
  
- **Area of the Semicircle:** Assuming the semicircle is centered at (5,1) with radius \( r = 1 \), the area under the semicircle from \( x = 4 \) to \( x = 6 \) is:

\[
\text{Area of semicircle} = \frac{1}{2} \pi r^2 = \frac{1}{2} \pi (1)^2 = \frac{\pi}{2}
\]

### Summing Up the Areas

Let’s assume the graph shows these calculations and areas. For example:

- **Area from \( x = 0 \) to \( x = 4 \) = \( A_1 \)**
- **Area of semicircle from \( x = 4 \) to \( x = 6 \) = \( \frac{\pi}{2} \)**
- **Area from \( x = 6 \) to \( x = 9 \) = \( A_2 \)**

### Total Integral Calculation

The definite integral is the sum of all these areas:

\[
\int_{0}^{9} f(x) \, dx = A_1 + \frac{\pi}{2} + A_2
\]

### Calculating \( F(9) \)

Now plug these areas into the formula for \( F(9) \):

\[
F(9) = F(0) + \int_{0}^{9} f(x) \, dx = 2 + (A_1 + \frac{\pi}{2} + A_2)
\]

Without the exact values of \( A_1 \) and \( A_2 \), we cannot compute an exact numeric value. However, if you provide these areas, we can substitute and solve.

### Conclusion

To find \( F(9) \), sum up all the known areas and add them to 2. If you have specific values for these areas, let’s plug them in!

---

Would you like to proceed with some hypothetical values or need further clarification on any steps?

### Related Questions

1. How do you calculate the area under a line segment in general?
2. What would change if the semicircle was below the x-axis?
3. Can we use numerical methods to estimate these areas if they aren't geometrically simple?
4. How would the integral be affected if the function had discontinuities?
5. How does the antiderivative change if \( F(0) \) was a different constant?

**Tip:** Always break down the integral into manageable segments to simplify area calculations.

Explore how to calculate F(9) for a continuous function represented by line segments and a semicircle, given an antiderivative F(x) such that F(0)=2. Learn about definite integrals, geometric area calculations under graphs, and applications of the Fundamental Theorem of Calculus.

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