Math Problem Statement

Given f(x) =

{9-x2, x<2

{ √x +7, 2≤x<10

{[x-4] ,x ≥ 10

(a) f(2)

Solution

To find f(2)f(2), we need to determine which part of the piecewise function f(x)f(x) applies when x=2x = 2.

The function f(x)f(x) is defined as:

\begin{cases} 9 - x^2, & \text{if } x < 2 \\ \sqrt{x} + 7, & \text{if } 2 \leq x < 10 \\ |x - 4|, & \text{if } x \geq 10 \end{cases}$$ Since $$x = 2$$ falls in the interval $$2 \leq x < 10$$, we use the second piece of the function: $$f(x) = \sqrt{x} + 7$$ Now, plug in $$x = 2$$: $$f(2) = \sqrt{2} + 7$$ $$f(2) = \sqrt{2} + 7 \approx 1.414 + 7 = 8.414$$ Therefore, $$f(2) = \sqrt{2} + 7$$. Would you like more details or have any questions? Here are 5 related questions to expand on this topic: 1. What is $$f(10)$$ for the given function? 2. How do you find $$f(x)$$ for values less than 2? 3. What is the domain of the function $$f(x)$$? 4. How would you graph this piecewise function? 5. What are the intervals where $$f(x)$$ is continuous? **Tip:** When working with piecewise functions, always pay attention to the conditions for each piece to determine which part of the function to use for specific values of $$x$$.

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Math Problem Analysis

Mathematical Concepts

Piecewise Functions
Square Root Function
Absolute Value Function

Formulas

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Theorems

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Suitable Grade Level

Grades 10-12