To solve these problems, let's break them down step by step.

Part 1: How many electrons are needed to form a charge of $-2.00 \, \text{nC}$?

We've already determined that the number of electrons needed to form a charge of $-2.00 \, \text{nC}$ is:

$n = \frac{-2.00 \times 10^{-9} \, \text{C}}{-1.60 \times 10^{-19} \, \text{C/electron}} = 1.25 \times 10^{10} \, \text{electrons}$

Part 2: How many electrons must be removed from a neutral object to leave a net charge of $0.500 \, \mu\text{C}$?

Again, we'll use the formula:

$Q = n \times e$

Given:

• $Q = 0.500 \, \mu\text{C} = 0.500 \times 10^{-6} \, \text{C}$
• $e = 1.60 \times 10^{-19} \, \text{C}$

To find the number of electrons $n$:

$n = \frac{Q}{e} = \frac{0.500 \times 10^{-6} \, \text{C}}{1.60 \times 10^{-19} \, \text{C/electron}}$

$n = 3.125 \times 10^{12} \, \text{electrons}$

Thus, $3.125 \times 10^{12}$ electrons must be removed from a neutral object to leave a net charge of $0.500 \, \mu\text{C}$.

Would you like more details or have any other questions?

Here are 5 related questions:

1. How would the required number of electrons change if the charge was $1.00 \, \mu\text{C}$?
2. What is the total charge if $6.25 \times 10^{12}$ electrons are removed from an object?
3. How does removing electrons from a neutral object affect its overall charge?
4. What practical methods are used to remove electrons from an object?
5. What is the significance of the Coulomb in electrical charge measurements?

Tip: When removing electrons from a neutral object, the object becomes positively charged. The more electrons you remove, the higher the positive charge.