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To solve for \(\frac{dp}{ds}\), we can use the chain rule. The chain rule states that:

\[
\frac{dp}{ds} = \frac{dp}{dt} \cdot \frac{dt}{ds}
\]

Given:
\[
\frac{dp}{dt} = 4 \quad \text{and} \quad \frac{dt}{ds} = 0.6
\]

Substituting the values into the chain rule formula:

\[
\frac{dp}{ds} = 4 \times 0.6 = 2.4
\]

So, the value of \(\frac{dp}{ds}\) is **2.4**.

Would you like further details or have any questions?

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Here are some related questions you might consider:
1. How does the chain rule apply to functions of multiple variables?
2. What would happen if the sign of \(\frac{dp}{dt}\) or \(\frac{dt}{ds}\) were negative?
3. Can the chain rule be extended to more than two variables?
4. How can this concept be applied in physics, for example, in kinematics?
5. What is the physical interpretation of each derivative in the context of real-world scenarios?

**Tip:** Always ensure that the functions involved are differentiable when applying the chain rule, as it is essential for the rule's validity.

If dp/dt = 4, and dt/ds = 0.6, what is dp/ds?

Learn how to calculate dp/ds using the Chain Rule when dp/dt = 4 and dt/ds = 0.6. This problem focuses on key calculus concepts and differentiation techniques. Suitable for students in Grades 11-12.

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