Math Problem Statement

Work out the length of AG in the cuboid below. Give your answer to 2 d.p.

Solution

To find the length of AGAG in the cuboid, let's break this down step-by-step:


Step 1: Understand the geometry of the cuboid

  • Given dimensions:

    • Length of AD=23cmAD = 23 \, \text{cm} (base along the bottom left edge).
    • Width of DC=18cmDC = 18 \, \text{cm} (base along the bottom right edge).
    • DAB=75\angle DAB = 75^\circ (angle between ADAD and ABAB).

    The diagonal AGAG runs from AA at the bottom front corner to GG, the farthest opposite top corner.


Step 2: Find ABAB using trigonometry

From DAB=75\angle DAB = 75^\circ and the length of AD=23cmAD = 23 \, \text{cm}, we can calculate ABAB using: AB=ADtan(75)AB = AD \cdot \tan(75^\circ) Substitute: AB=23tan(75)AB = 23 \cdot \tan(75^\circ) Using tan(75)3.732\tan(75^\circ) \approx 3.732: AB233.732=85.84cmAB \approx 23 \cdot 3.732 = 85.84 \, \text{cm}


Step 3: Find ACAC, the diagonal of the base

The diagonal ACAC can be found using the Pythagorean theorem, as ACAC is the hypotenuse of the triangle ADC\triangle ADC: AC=AD2+DC2AC = \sqrt{AD^2 + DC^2} Substitute: AC=232+182=529+324=853AC = \sqrt{23^2 + 18^2} = \sqrt{529 + 324} = \sqrt{853} AC29.23cmAC \approx 29.23 \, \text{cm}


Step 4: Find AGAG, the diagonal of the cuboid

Now, AGAG is the diagonal of the cuboid, and it can be calculated as the hypotenuse of the triangle ACG\triangle ACG, where:

  • AC=29.23cmAC = 29.23 \, \text{cm} (diagonal of the base).
  • Height CG=AB=85.84cmCG = AB = 85.84 \, \text{cm}.

Using the Pythagorean theorem again: AG=AC2+CG2AG = \sqrt{AC^2 + CG^2} Substitute: AG=(29.23)2+(85.84)2AG = \sqrt{(29.23)^2 + (85.84)^2} Calculate: AG=854.32+7370.71=8225.03AG = \sqrt{854.32 + 7370.71} = \sqrt{8225.03} AG90.68cmAG \approx 90.68 \, \text{cm}


Final Answer:

The length of AGAG is approximately: 90.68cm\boxed{90.68 \, \text{cm}}


Would you like more details on any of the steps, or have additional questions?


Related Questions:

  1. How would the solution change if the angle DAB\angle DAB were 6060^\circ instead of 7575^\circ?
  2. What is the formula for the diagonal of a cuboid in terms of its dimensions?
  3. How is ACAC, the diagonal of the base, derived geometrically in cuboids?
  4. What is the significance of the trigonometric function tan\tan in finding ABAB?
  5. Can you generalize the calculation for any cuboid when all three dimensions are known?

Tip:

For 3D geometry problems, always break down the diagonal into smaller triangles to apply the Pythagorean theorem step by step.

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Math Problem Analysis

Mathematical Concepts

3D Geometry
Trigonometry
Pythagoras' Theorem

Formulas

tan(θ) = opposite / adjacent
Pythagorean theorem: a^2 + b^2 = c^2

Theorems

Trigonometric Functions
Pythagorean Theorem

Suitable Grade Level

Grades 10-12