a block of wood measuring 30mm X 0.05cm has a mass f 0.15kg. Calculate te density and the specific gravity of the block of wood.

To solve this problem, we will calculate the **density** and the **specific gravity** of the block of wood using the given dimensions and mass.

### Step 1: Convert dimensions to consistent units
- The dimensions are given as:
  - Length = 30 mm
  - Width = 0.05 cm

First, let's convert these dimensions to **meters** for consistency:
- 30 mm = \(30 \times 10^{-3}\) meters = 0.03 meters
- 0.05 cm = \(0.05 \times 10^{-2}\) meters = 0.0005 meters

Since only two dimensions are given, we assume the third dimension is along the depth or thickness of the block. However, the depth isn't specified. Without this, we cannot proceed directly with a standard volume-based calculation. If the depth (thickness) was known or inferred, the formula for density would be applied as follows:

### Step 2: Formula for density
The **density** \(\rho\) is calculated as:

\[
\rho = \frac{m}{V}
\]

Where:
- \(m\) is the mass (0.15 kg),
- \(V\) is the volume of the block (in cubic meters).

However, since the volume is missing, we need clarification on this to proceed accurately. Could you specify the missing dimension?

Feel free to ask for further clarification or submit new data!

A block of wood measuring 30mm X 0.05cm has a mass of 0.15kg. Calculate the density and the specific gravity of the block of wood.

Learn how to calculate the density and specific gravity of a block of wood with given dimensions (30mm X 0.05cm) and mass (0.15kg). Includes unit conversion techniques and key formulas such as the density and specific gravity equations. Suitable for students in Grades 10-12.

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