What is the density of a 700 kg object with a volume of 649 m3?

0.927 kg/m3
.4543 kg/m3
1.079 kg/m3
4.543 kg/m3

The formula for density is:

\[
D = \frac{m}{v}
\]

Where:
- \(m = 700 \, \text{kg}\) (mass),
- \(v = 649 \, \text{m}^3\) (volume).

Substituting the values:

\[
D = \frac{700 \, \text{kg}}{649 \, \text{m}^3} \approx 1.079 \, \text{kg/m}^3
\]

So, the density of the object is approximately **1.079 kg/m³**, which matches the third option.

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Would you like to explore further details or ask any questions?

Here are 5 related questions:
1. How would the density change if the mass were doubled while keeping the volume constant?
2. What role does density play in determining whether an object will sink or float in water?
3. How is density different from specific gravity?
4. Can density change if the shape of the object changes while keeping mass and volume constant?
5. What are some common applications of density in engineering and science?

**Tip:** Always verify that the units of mass and volume are consistent to avoid incorrect density calculations!

What is the density of a 700 kg object with a volume of 649 m3?

Discover how to calculate the density of a 700 kg object with a volume of 649 m³. Using the formula D = m/v, this problem demonstrates a key physics concept of density. Learn step-by-step how to derive the solution with detailed explanations. Ideal for middle school students (Grades 6-8).

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