Math Problem Statement

A power station is on one side of a river that is 3/4 miles wide, and a factory is 8 miles downstream on the other side of the river. It costs $24 per foot to run power lines over land and $30 per foot to run them under water. The project's cost is $1,103,149.53. Find the length x labeled in the figure. (Enter your answers as a comma-separated list. Round your answers to three decimal places.)

Solution

Let me summarize the given situation and define the variables:

  • The river is 34\frac{3}{4} miles wide.
  • The factory is 8 miles downstream.
  • The cost per foot for laying power lines over land is $24/foot.
  • The cost per foot for laying power lines under water is $30/foot.
  • The total cost for the project is $1,103,149.53.

Step 1: Understand the Problem

From the problem, there are two different paths where the power lines can be laid:

  1. Underwater across the width of the river for a distance of xx (in miles).
  2. On land for a remaining distance, covering the rest of the 8 miles minus xx along the riverbank.

Step 2: Set Up the Cost Function

Convert all distances to feet:

  • 1 mile = 5280 feet, so:
    • The width of the river: 34×5280=3960\frac{3}{4} \times 5280 = 3960 feet.
    • The total downstream distance (8 miles): 8×5280=42,2408 \times 5280 = 42,240 feet.

Let xx be the horizontal distance underwater (in miles). We need to compute the total cost of laying power lines.

  • Underwater segment cost: The underwater path has a length of x2+(0.75)2\sqrt{x^2 + (0.75)^2} miles (since it's the hypotenuse of a right triangle with the river width and xx). In feet, this is: underwater distance (feet)=5280×x2+(0.75)2\text{underwater distance (feet)} = 5280 \times \sqrt{x^2 + (0.75)^2} The cost for laying this underwater segment is: 30×5280×x2+0.75230 \times 5280 \times \sqrt{x^2 + 0.75^2}

  • Land segment cost: The remaining land distance is 8x8 - x miles, or 5280×(8x)5280 \times (8 - x) feet. The cost for laying the power lines on land is: 24×5280×(8x)24 \times 5280 \times (8 - x)

Step 3: Total Cost

The total cost of the project is given by: 30×5280×x2+0.752+24×5280×(8x)=1,103,149.5330 \times 5280 \times \sqrt{x^2 + 0.75^2} + 24 \times 5280 \times (8 - x) = 1,103,149.53 Simplify: 158400×x2+0.752+126720×(8x)=1,103,149.53158400 \times \sqrt{x^2 + 0.75^2} + 126720 \times (8 - x) = 1,103,149.53

Step 4: Solve for xx

We can solve this equation numerically for xx. Let me calculate the value of xx.The value of xx, the horizontal distance underwater, is approximately 2.2002.200 miles.

Would you like further details on how this was calculated or any other clarifications?

Here are 5 follow-up questions to consider:

  1. How would the total cost change if the underwater cost per foot was reduced to $25?
  2. What is the land distance that the power lines will cover based on this solution?
  3. How would the solution change if the river were wider, say 1 mile instead of 34\frac{3}{4} miles?
  4. Can you derive a general formula to determine the cost based on different river widths and downstream distances?
  5. What are the practical challenges in laying power lines underwater versus on land?

Tip: When solving real-world problems, setting up equations based on distances and costs is key to finding the optimal solution.

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Math Problem Analysis

Mathematical Concepts

Geometry
Pythagorean Theorem
Optimization
Cost Analysis

Formulas

Pythagorean Theorem: a^2 + b^2 = c^2
Cost Function: Total cost = (underwater cost per foot) × (underwater distance in feet) + (land cost per foot) × (land distance in feet)
Distance Conversion: 1 mile = 5280 feet

Theorems

Pythagorean Theorem

Suitable Grade Level

Grades 10-12