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The image shows a compound interest problem. You are asked to find how much money will be in the account after 2.5 years, given:

- Principal (P): $4,500
- Annual interest rate (r): 2.7%
- Compound frequency: Daily (365 times a year)
- Time (t): 2.5 years

We can use the compound interest formula to solve this:

\[
A = P \left( 1 + \frac{r}{n} \right)^{nt}
\]

Where:
- $ A $ is the amount of money in the account after time $ t $
- $ P $ is the principal amount ($4,500)
- $ r $ is the annual interest rate (2.7% or 0.027 as a decimal)
- $ n $ is the number of times the interest is compounded per year (365)
- $ t $ is the time the money is invested (2.5 years)

Let's plug in the values:

\[
A = 4500 \left( 1 + \frac{0.027}{365} \right)^{365 \times 2.5}
\]

Now, solving for $ A $:

\[
A = 4500 \left( 1 + 0.00007397 \right)^{912.5}
\]
\[
A = 4500 \left( 1.00007397 \right)^{912.5}
\]
\[
A \approx 4500 \times 1.0696 = 4813.37
\]

So, the amount of money in the account after 2.5 years is approximately **$4,813.37**.

Would you like further details or have any other questions?

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Here are some related questions for practice:
1. How would the amount change if the interest rate were 3.5%?
2. What would the final amount be if the interest was compounded monthly instead of daily?
3. How does compound interest differ from simple interest?
4. What happens if the time is reduced to 1 year?
5. What would happen if the principal were $5,000 instead?

**Tip:** Compounding more frequently (like daily) increases the total interest earned compared to less frequent compounding (like annually).

Find how much money will be in the account after 2.5 years with a principal of $4500, an interest rate of 2.7% compounded daily.

Learn how to calculate compound interest for an initial principal of $4500 at an interest rate of 2.7%, compounded daily over 2.5 years. Use the compound interest formula to find the final amount in the account.

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