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The question asks to calculate the interest earned on a deposit of $14,000 for six years at an Annual Percentage Rate (APR) of 3%, with interest compounded quarterly. 

We can use the compound interest formula:

\[
A = P \left(1 + \frac{r}{n}\right)^{nt}
\]

Where:
- $A$ is the amount of money accumulated after interest,
- $P$ is the principal amount (initial deposit) = $14,000,
- $r$ is the annual interest rate (decimal) = 3% = 0.03,
- $n$ is the number of times the interest is compounded per year = 4 (quarterly),
- $t$ is the time the money is invested for, in years = 6.

The interest earned is then:

\[
\text{Interest} = A - P
\]

Let's calculate it.The interest earned on a deposit of $14,000 at 3% APR, compounded quarterly for six years, is approximately **$2,749.79**.

Would you like any more details or have any questions about this process?

Here are five related questions you might be interested in:
1. How does the frequency of compounding affect the total interest earned?
2. What would the interest be if the APR was higher, say 5%?
3. How would the interest change if the deposit term was only 3 years instead of 6?
4. What is the formula for continuously compounded interest, and how would it apply here?
5. How much would be earned if the compounding were done annually instead of quarterly?

**Tip:** The more frequently interest is compounded, the more interest you will earn on your investment.

Suppose that $14,000 is deposited for six years at 3% APR. Calculate the interest earned if interest is compounded quarterly. Round your answer to the nearest cent.

Learn how to calculate the interest earned on a deposit of $14,000 over six years at a 3% APR with quarterly compounding. This example uses the compound interest formula and explains how to calculate the total interest earned. Suitable for high school students.

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