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To solve the problem based on the provided information, we will use the compound interest formula:

\[
A = P \left(1 + \frac{r}{n}\right)^{nt}
\]

Where:
- $ P = 10,000 $ (the principal investment),
- $ r = 3.5\% = 0.035 $ (the annual interest rate),
- $ n = 12 $ (since the interest is compounded monthly),
- $ t = 4 $ years (the time the money is invested for).

Let's plug the values into the formula and calculate the amount $ A $ after 4 years.

\[
A = 10,000 \left(1 + \frac{0.035}{12}\right)^{12 \times 4}
\]

\[
A = 10,000 \left(1 + 0.00291667\right)^{48}
\]

\[
A = 10,000 \left(1.00291667\right)^{48}
\]

Now, calculating $ \left(1.00291667\right)^{48} $:

\[
A = 10,000 \times 1.149744
\]

\[
A \approx 11,497.44
\]

So, the amount of money in the account after 4 years is approximately **$11,497.44**.

Would you like a more detailed breakdown or explanation? 

Here are 5 related questions for further practice:
1. What will the balance be after 6 years with the same conditions?
2. How much interest will be earned after 4 years?
3. If the rate was 4% instead of 3.5%, what would the amount be after 4 years?
4. How does the frequency of compounding (monthly vs quarterly) affect the final amount?
5. What would the effective annual yield (Y) be with this setup?

**Tip:** The more frequent the compounding, the more interest will be earned over time!

Find how much money there will be in the account after the given number of years. The amount of money in the account after 4 years is $_______. (Given: Principal = $10,000, Rate = 3.5%, Compounded monthly, Time = 4 years)

Learn how to calculate the compound interest for an investment of $10,000 with a 3.5% annual interest rate compounded monthly over a period of 4 years. The solution includes a step-by-step breakdown using the compound interest formula. Suitable for students in Grades 10-12.

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