Math Problem Statement

A research team has 18 variables and wants to form 4 clusters. Each cluster must have at least 3 variables, and no two clusters can have the same number of variables. How many different clustering configurations are possible?

Solution

To solve this problem, we need to determine how to distribute 18 variables into 4 clusters such that each cluster has at least 3 variables and no two clusters have the same number of variables.

Step 1: Define the problem constraints

  • Total variables: 18
  • Total clusters: 4
  • Minimum variables per cluster: 3
  • No two clusters can have the same number of variables.

Step 2: Possible cluster configurations

Since each cluster must have a different number of variables and at least 3 variables, we can list the possible distributions. Let's denote the number of variables in each cluster as a,b,c,a, b, c, and dd such that a<b<c<da < b < c < d.

Step 3: Satisfying the conditions

The sum of all variables in the clusters must equal 18:

a+b+c+d=18a + b + c + d = 18

Each of a,b,c,a, b, c, and dd must be different and at least 3. Let's try to find values that satisfy all these conditions.

Step 4: Finding valid combinations

  • Start with a=3a = 3 (smallest possible value).
    • Then b=4b = 4 (next smallest possible value).

      • a+b=3+4=7a + b = 3 + 4 = 7, so c+d=187=11c + d = 18 - 7 = 11.
      • To satisfy c<dc < d and both being greater than bb, choose c=5c = 5 and d=6d = 6.

      This gives us one valid configuration:

      a=3,b=4,c=5,d=6a = 3, \quad b = 4, \quad c = 5, \quad d = 6

Step 5: Counting the permutations

The configuration (3,4,5,6)(3, 4, 5, 6) is one valid configuration in terms of sizes, but we need to count how these variables can be assigned to the clusters.

The number of ways to arrange the sizes (3, 4, 5, 6) to specific clusters is simply a permutation of 4 distinct items:

4!=4×3×2×1=244! = 4 \times 3 \times 2 \times 1 = 24

Thus, there are 24 different clustering configurations possible under the given conditions.

Final Answer

There are 24 different clustering configurations possible.

Would you like more details or have any questions?

Related Questions:

  1. What if the minimum number of variables per cluster was increased to 4? How would that affect the possible configurations?
  2. How many different configurations are possible if we had 5 clusters instead of 4, while still maintaining the other conditions?
  3. If we relaxed the condition of having at least 3 variables per cluster, how many configurations would be possible?
  4. How does the number of variables and clusters affect the complexity of finding the clustering configurations?
  5. What if the clusters had to have consecutive even numbers of variables? How many configurations would be possible then?

Tip:

When solving problems involving permutations and combinations, it often helps to list out constraints first and start with the smallest possible values to find valid configurations.

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Math Problem Analysis

Mathematical Concepts

Combinatorics
Permutations
Constraints in Combinations

Formulas

Permutation formula: nPr = n! / (n - r)!

Theorems

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Suitable Grade Level

Advanced High School