Math Problem Statement
Calculate the number of BTU’s required to change 584 lbs. of steam at 290°F to 584 lbs. of ice at 25°F.
specific heat of ice = 0.5
specific heat of water = 1.0
specific heat of steam = 0.5
latent heat of melting = 144
latent heat of boiling = 970
Solution
To calculate the number of BTUs required to convert 584 lbs of steam at 290°F into 584 lbs of ice at 25°F, we need to consider several stages of heat transfer:
- Cooling steam from 290°F to 212°F (condensation point).
- Condensing steam at 212°F into water.
- Cooling water from 212°F to 32°F (freezing point).
- Freezing water at 32°F into ice.
- Cooling ice from 32°F to 25°F.
We'll calculate the BTUs for each stage.
1. Cooling Steam from 290°F to 212°F
2. Condensing Steam to Water at 212°F
3. Cooling Water from 212°F to 32°F
4. Freezing Water to Ice at 32°F
5. Cooling Ice from 32°F to 25°F
Total BTUs Required
Therefore, 780,492 BTUs are required to change 584 lbs of steam at 290°F to 584 lbs of ice at 25°F.
Would you like more details or have any questions?
Here are some related questions:
- How does latent heat impact phase changes?
- What is the significance of specific heat in temperature changes?
- Why is the latent heat of boiling so much higher than the latent heat of melting?
- How do pressure changes affect the boiling point of water?
- What role does energy conservation play in heat transfer problems?
Tip: Always double-check temperature differences and phase changes when dealing with heat transfer problems to ensure correct use of latent and specific heat values.
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Math Problem Analysis
Mathematical Concepts
Thermodynamics
Heat Transfer
Phase Changes
Formulas
Q = m * C * ΔT
Q = m * Latent Heat
Theorems
Law of Conservation of Energy
Specific Heat Capacity
Latent Heat of Melting and Boiling
Suitable Grade Level
College Level (Thermodynamics/Physics)
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