To find the average velocity of an object falling freely for 8 seconds, we can use the following relationship for free fall under constant acceleration due to gravity ($g \approx 9.8 \, \text{m/s}^2$):

The average velocity $v_{\text{avg}}$ in uniformly accelerated motion is given by: $v_{\text{avg}} = \frac{v_{\text{initial}} + v_{\text{final}}}{2}$

For an object falling freely from rest, the initial velocity $v_{\text{initial}}$ is 0, and the final velocity after $t$ seconds is given by the formula: $v_{\text{final}} = g \cdot t$

Given:

• $t = 8 \, \text{seconds}$
• $g = 9.8 \, \text{m/s}^2$

Now, calculate the final velocity: $v_{\text{final}} = 9.8 \cdot 8 = 78.4 \, \text{m/s}$

The average velocity: $v_{\text{avg}} = \frac{0 + 78.4}{2} = 39.2 \, \text{m/s}$

Thus, the average velocity is 39.2 m/s.

Would you like more details or have any questions?

Here are 5 related questions:

1. How far does the object travel in 8 seconds?
2. How does the time of fall affect the final velocity?
3. What is the velocity after 5 seconds of free fall?
4. How would air resistance affect the motion of a falling object?
5. How does gravity vary on different planets?

Tip: Average velocity in uniformly accelerated motion can always be found by averaging the initial and final velocities.