Mr Morrison travels from Melbourne CBD out bound to Burwood at a speed of 83km/h and returns to same speed of 28km/h die to congestion. What is the average speed of the round trip 

To find the average speed of the round trip, we need to use the formula for average speed when the speed is different in each direction. The formula is:

\[
\text{Average Speed} = \frac{2 \times v_1 \times v_2}{v_1 + v_2}
\]

Where:
- \(v_1\) is the speed going from Melbourne CBD to Burwood (83 km/h),
- \(v_2\) is the speed returning from Burwood to Melbourne CBD (28 km/h).

Substituting the given values:

\[
\text{Average Speed} = \frac{2 \times 83 \times 28}{83 + 28}
\]

Now, let's calculate it.

\[
\text{Average Speed} = \frac{2 \times 83 \times 28}{111} = \frac{4648}{111} \approx 41.88 \text{ km/h}
\]

So, the average speed of the round trip is approximately **41.88 km/h**.

Would you like more details, or do you have any questions?

Here are five related questions for further exploration:
1. How would the average speed change if the return speed increased to 50 km/h?
2. What is the total time taken for the entire round trip?
3. How far is Burwood from Melbourne CBD if the entire trip took 2 hours?
4. How does congestion affect average speed and travel time?
5. How would the average speed change if Mr. Morrison took a different route with varying speeds?

**Tip:** Remember that average speed is not simply the average of the two speeds. It depends on the time spent traveling at each speed.

Learn how to calculate the average speed of a round trip from Melbourne CBD to Burwood and back. Mr. Morrison travels at 83 km/h outbound and 28 km/h inbound due to congestion. Understand the formula for average speed in round trips and apply it to find the solution. Suitable for students in Grades 7-9.

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