The image provides the problem of finding the area of a triangle, where the formula is given as:

$\text{Area} = \frac{1}{2} \cdot \text{base} \cdot \text{height}$

In this case, the base of the triangle is $13 \, \text{m}$ and the height is $4 \, \text{m}$.

Using the formula:

$\text{Area} = \frac{1}{2} \cdot 13 \, \text{m} \cdot 4 \, \text{m}$

Let me calculate that.The area of the triangle is $26 \, \text{m}^2$.

Would you like more details or have any other questions?

Here are some related questions you might find interesting:

1. How would the area change if both the base and height were doubled?
2. Can the Pythagorean theorem be applied to this triangle, and if so, how?
3. How is the formula for the area of a triangle derived?
4. What happens to the area if only the height is doubled while the base remains the same?
5. What is the significance of the factor $\frac{1}{2}$ in the area formula for triangles?

Tip: Always make sure to use the correct units when working with area formulas—here, meters squared $\text{m}^2$.