The problem in the image is asking for the area of a right triangle, where the base is 6 units and the height is 3 units.

The formula for the area of a triangle is:

$\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}$

Substitute the given values:

$\text{Area} = \frac{1}{2} \times 6 \times 3 = \frac{1}{2} \times 18 = 9 \, \text{units}^2$

Thus, the area of the triangle is 9 square units.

Do you want more details or have any questions?

Here are five related questions for you to consider:

1. What is the formula for the area of an equilateral triangle?
2. How do you calculate the area of a triangle given all three sides?
3. What is the Pythagorean theorem and how can it apply to right triangles?
4. If the height of a triangle was doubled, how would the area change?
5. Can you calculate the perimeter of the triangle using the Pythagorean theorem?

Tip: For any right triangle, the Pythagorean theorem can help you find the third side when two sides are known.