Math Problem Statement

An architect is designing a building. The original design of the building has a length and width of 6x meters. The owner of the building decides to increase the length of the building by 15 meters and decrease the width by 15 meters for the new design. Which expression represents the area of the building for the new design?

Solution

Let's analyze the problem step by step:

Given:

  1. Original dimensions:

    • Length: 6x6x meters
    • Width: 6x6x meters
  2. Changes to dimensions:

    • Length is increased by 15 meters: 6x+156x + 15
    • Width is decreased by 15 meters: 6x156x - 15
  3. New area expression: The new area of the building will be the product of the new length and width: A=New Length×New WidthA = \text{New Length} \times \text{New Width} Substituting the expressions: A=(6x+15)(6x15)A = (6x + 15)(6x - 15)

  4. Simplify using the difference of squares: A=(6x)2(15)2A = (6x)^2 - (15)^2 A=36x2225A = 36x^2 - 225

Final Answer:

The expression that represents the area for the new design is: A=36x2225A = 36x^2 - 225

If you'd like further explanation or have any questions, let me know!


Here are 5 related questions to practice with:

  1. What happens to the new area if x=5x = 5?
  2. How would the formula change if the length were increased by 10 meters instead of 15?
  3. What is the perimeter of the new design in terms of xx?
  4. If the width decrease was only 10 meters, how would the expression for the new area look?
  5. How can you determine the original area of the building?

Tip:

Always check for opportunities to simplify expressions, such as using the difference of squares, when dealing with products like (a+b)(ab)(a+b)(a-b).

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Math Problem Analysis

Mathematical Concepts

Algebra
Area Calculation
Difference of Squares

Formulas

Area of a rectangle = length × width
Difference of squares: (a + b)(a - b) = a^2 - b^2

Theorems

Difference of Squares

Suitable Grade Level

Grades 8-10