Math Problem Statement

Triangle XYZ has an obtuse angle at Z. If XY = 15cm, YZ = 10cm and angle YXZ = 31° find the size of angle XZY in degrees.

Solution

To find the size of angle XZY\angle XZY in triangle XYZ, we can use the Law of Sines or the Law of Cosines. However, because we are given two sides and the included angle, the Law of Cosines is more appropriate for solving this problem.

Step 1: Apply the Law of Cosines

The Law of Cosines states that for any triangle ABCABC: c2=a2+b22abcosCc^2 = a^2 + b^2 - 2ab \cos C where cc is the side opposite angle CC, and aa and bb are the other two sides.

In triangle XYZ:

  • XY=c=15cmXY = c = 15 \, \text{cm}
  • YZ=a=10cmYZ = a = 10 \, \text{cm}
  • XZ=bXZ = b
  • YXZ=C=31\angle YXZ = C = 31^\circ

We first need to find the length of XZXZ using the Law of Cosines.

Step 2: Calculate XZXZ

XZ2=XY2+YZ22×XY×YZ×cos(YXZ)XZ^2 = XY^2 + YZ^2 - 2 \times XY \times YZ \times \cos(\angle YXZ) XZ2=152+1022×15×10×cos(31)XZ^2 = 15^2 + 10^2 - 2 \times 15 \times 10 \times \cos(31^\circ) XZ2=225+100300×cos(31)XZ^2 = 225 + 100 - 300 \times \cos(31^\circ) XZ2=325300×0.8572XZ^2 = 325 - 300 \times 0.8572 XZ2=325257.16XZ^2 = 325 - 257.16 XZ2=67.84XZ^2 = 67.84 XZ=67.848.24cmXZ = \sqrt{67.84} \approx 8.24 \, \text{cm}

Step 3: Apply the Law of Sines to find XZY\angle XZY

The Law of Sines states: sinAa=sinBb=sinCc\frac{\sin A}{a} = \frac{\sin B}{b} = \frac{\sin C}{c} We use the ratios involving XZY\angle XZY and YXZ\angle YXZ: sin(XZY)YZ=sin(YXZ)XZ\frac{\sin(\angle XZY)}{YZ} = \frac{\sin(\angle YXZ)}{XZ} sin(XZY)10=sin(31)8.24\frac{\sin(\angle XZY)}{10} = \frac{\sin(31^\circ)}{8.24} sin(XZY)=10×sin(31)8.24\sin(\angle XZY) = \frac{10 \times \sin(31^\circ)}{8.24} sin(XZY)=10×0.51508.24\sin(\angle XZY) = \frac{10 \times 0.5150}{8.24} sin(XZY)=5.158.240.625\sin(\angle XZY) = \frac{5.15}{8.24} \approx 0.625

Step 4: Find XZY\angle XZY

XZY=arcsin(0.625)38.7\angle XZY = \arcsin(0.625) \approx 38.7^\circ

Thus, the size of XZY\angle XZY is approximately 38.7 degrees.

Would you like further details or have any questions about this solution? Here are five related questions you might explore:

  1. How does the Law of Cosines differ from the Law of Sines in application?
  2. What are the steps to determine if a triangle is obtuse?
  3. How do you calculate the area of triangle XYZ using the given sides and angles?
  4. Can you solve for the remaining angle YZX\angle YZX in triangle XYZ?
  5. How does the cosine of an angle relate to the type of triangle (acute, obtuse, or right)?

Tip: When solving for angles in a triangle, always check if your calculated angles make sense within the context of the problem (e.g., whether they sum up to 180° in a triangle).

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Math Problem Analysis

Mathematical Concepts

Geometry
Trigonometry

Formulas

Law of Cosines
Law of Sines

Theorems

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Suitable Grade Level

High School