5)If a solution  contains 30% of sulphur, how much solution  is required to obtain 150g of sulphur?

We are given that the solution contains 30% sulfur, and we need to obtain 150 grams of sulfur. Let's define the variables:

- Let \( x \) be the amount of solution required (in grams).
- Since the solution is 30% sulfur, the amount of sulfur in the solution will be \( 0.30x \).

To get 150 grams of sulfur, we set up the following equation:

\[
0.30x = 150
\]

Now, solve for \( x \):

\[
x = \frac{150}{0.30} = 500 \, \text{grams}
\]

Thus, **500 grams** of the solution is required to obtain 150 grams of sulfur.

Would you like any further clarification or details on this calculation? Here are five related questions for further exploration:

1. What would be the amount of solution needed if it contained 20% sulfur instead of 30%?
2. How much sulfur is present in 250 grams of a 40% sulfur solution?
3. If a solution has 50% sulfur, how much of the solution is needed to obtain 200 grams of sulfur?
4. If you only have 100 grams of a 30% sulfur solution, how much sulfur is present in it?
5. What is the mass of sulfur in 600 grams of a 25% sulfur solution?

**Tip:** To solve percentage problems involving mixtures or solutions, remember that the percentage is a fraction of the total amount, which you can represent mathematically as multiplication by the decimal form of the percentage (e.g., 30% is 0.30).

If a solution contains 30% of sulfur, how much solution is required to obtain 150g of sulfur?

Learn how to calculate the amount of a 30% sulfur solution required to obtain 150g of sulfur with this step-by-step guide. Using percentage formulas and basic algebra, this problem is ideal for middle school students in Grades 6-8.

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