a submarine was cruising at -132 meters. It then climbed to -64 and 1 half meters. What was the difference between its original altitude and its later atitude

To calculate the difference in altitude, we subtract the initial altitude from the later altitude:

- Initial altitude: \(-132 \, \text{meters}\)
- Later altitude: \(-64 \frac{1}{2} \, \text{meters}\) or \(-64.5 \, \text{meters}\)

The difference is:

\[
\text{Difference} = \text{Later altitude} - \text{Initial altitude} = (-64.5) - (-132)
\]

This simplifies to:

\[
\text{Difference} = -64.5 + 132 = 67.5 \, \text{meters}
\]

Thus, the submarine climbed by **67.5 meters**.

Would you like more details or have any questions? Here are five related questions to expand on this problem:

1. What is the absolute distance between two negative altitudes?
2. If the submarine continued to climb by another 50 meters, what would its new altitude be?
3. How would the calculation change if the submarine descended instead of climbing?
4. How can we represent this climb graphically on a number line?
5. What is the significance of negative altitude in terms of sea level?

**Tip**: When subtracting a negative number, it becomes an addition!

A submarine was cruising at -132 meters. It then climbed to -64 and 1 half meters. What was the difference between its original altitude and its later altitude?

Learn how to find the difference in altitude between a submarine's initial position at -132 meters and its later position at -64.5 meters. This problem covers key arithmetic concepts, including subtraction of negative numbers, and is suitable for students in Grades 6-8.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation