Math Problem Statement

An airplane is flying due east with a speed of 600 mph. There is a wind blowing at 85 mph at an angle of S 59° E.

Determine the actual speed and angle of the airplane's flight.

Solution

To determine the actual speed and angle of the airplane's flight, we need to break this problem down into vector components.

Step 1: Define the airplane and wind velocity vectors

  • Airplane velocity: The airplane is flying due east with a speed of 600 mph. This is purely in the east direction, so its velocity vector can be written as: vairplane=(600,0) mph\vec{v}_{\text{airplane}} = (600, 0) \text{ mph}

  • Wind velocity: The wind is blowing at 85 mph at an angle of S 59° E. This angle means 59° south of the east direction, or 31° below the east axis. We can resolve this wind velocity into its x and y components: vwind=(vx,vy)\vec{v}_{\text{wind}} = (v_x, v_y) where vx=85cos(59)v_x = 85 \cos(59^\circ) vy=85sin(59)v_y = -85 \sin(59^\circ) (The y-component is negative because the wind is blowing southward.)

Step 2: Add the airplane and wind vectors

The total velocity of the airplane will be the vector sum of the airplane's velocity and the wind's velocity: vtotal=vairplane+vwind=(600+vx,0+vy)\vec{v}_{\text{total}} = \vec{v}_{\text{airplane}} + \vec{v}_{\text{wind}} = (600 + v_x, 0 + v_y)

Step 3: Determine the magnitude and angle of the resultant velocity

The magnitude of the total velocity (i.e., the actual speed of the airplane) is given by: vtotal=(600+vx)2+vy2|\vec{v}_{\text{total}}| = \sqrt{(600 + v_x)^2 + v_y^2} The direction (angle) of the airplane's flight relative to the east direction is given by: θ=tan1(vy600+vx)\theta = \tan^{-1}\left(\frac{v_y}{600 + v_x}\right)

Now, let's calculate these values.import math

Given values

airplane_speed = 600 # mph wind_speed = 85 # mph wind_angle = 59 # degrees south of east

Resolve wind velocity into components

v_x = wind_speed * math.cos(math.radians(wind_angle)) # east component v_y = -wind_speed * math.sin(math.radians(wind_angle)) # south component (negative because southward)

Calculate the resultant velocity components

total_v_x = airplane_speed + v_x total_v_y = v_y

Calculate the magnitude (speed) of the resultant velocity

actual_speed = math.sqrt(total_v_x2 + total_v_y2)

Calculate the direction (angle) of the resultant velocity

angle = math.degrees(math.atan2(total_v_y, total_v_x))

Output the actual speed and angle

actual_speed, angleThe actual speed of the airplane is approximately 647.89 mph, and the angle of its flight relative to due east is approximately 6.46° south of east.

Would you like further details or have any questions?

Here are 5 related questions you might find interesting:

  1. How would the result change if the wind were blowing at a different angle?
  2. What would the speed and direction be if the wind were blowing from the north instead of south?
  3. How can we use vector components in 3D motion, such as with airplanes changing altitude?
  4. How would the airplane's ground speed change if the wind speed increased?
  5. Can you calculate the time it would take for the airplane to travel 1000 miles given its actual speed?

Tip: When working with vectors, always break them into components along known axes (like x and y) to simplify complex problems.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Vectors
Velocity
Trigonometry

Formulas

Vector addition
Magnitude of a vector
Vector components

Theorems

-

Suitable Grade Level

High School