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The problem states:

- It takes **6.4 pounds of seed** to plant **1 acre** of grass.
- How many acres can be planted with **7.68 pounds** of seed?

This is a direct proportionality question. We can set up the ratio:

\[
\frac{6.4 \text{ pounds}}{1 \text{ acre}} = \frac{7.68 \text{ pounds}}{x \text{ acres}}
\]

Now, solve for \(x\), which represents the number of acres:

\[
x = \frac{7.68 \text{ pounds}}{6.4 \text{ pounds per acre}} = 1.2 \text{ acres}
\]

Therefore, **1.2 acres** can be planted with 7.68 pounds of seed.

Would you like further explanation, or do you have any other questions?

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Here are five related questions:

1. How would the solution change if the amount of seed per acre changed?
2. If you had 10 pounds of seed, how many acres could be planted?
3. What is the unit rate (pounds of seed per acre) for the above problem?
4. If the seed was measured in kilograms instead of pounds, how would that affect the calculation?
5. How many acres can be planted with 15 pounds of seed?

**Tip**: When solving proportional problems, setting up a ratio allows you to find unknown values easily by cross-multiplying and solving for the variable.

If it takes 6.4 pounds of seed to plant one acre of grass, how many acres can be planted with 7.68 pounds of seed?

Learn how to calculate how many acres can be planted with 7.68 pounds of seed when it takes 6.4 pounds to plant one acre. This proportionality problem involves simple ratios and is suitable for Grades 6-8.

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