A squirrel is water skiing behind a boat. The boat is going 8 m/s and then speeds up to 23 m/s in 7 seconds.  What is the squirrel’s acceleration? *Round to the hundredths place.* Enter numbers only.


To calculate the acceleration, we use the formula:

\[
a = \frac{{v_f - v_i}}{{t}}
\]

Where:
- \( v_f = 23 \, \text{m/s} \) (final velocity),
- \( v_i = 8 \, \text{m/s} \) (initial velocity),
- \( t = 7 \, \text{seconds} \) (time interval).

Now, substituting the values:

\[
a = \frac{{23 - 8}}{7} = \frac{15}{7} \approx 2.14 \, \text{m/s}^2
\]

The squirrel’s acceleration is **2.14** m/s².

Would you like more details or explanations?

Here are 5 related questions:
1. What is the velocity after 3 seconds of acceleration?
2. What is the distance traveled during the acceleration period?
3. How would the acceleration change if the time increased to 10 seconds?
4. What would the acceleration be if the final velocity was 30 m/s?
5. How long would it take to reach 50 m/s at the same acceleration?

**Tip:** Always keep track of units when solving physics problems—it's crucial to getting the right answer!

A squirrel is water skiing behind a boat. The boat is going 8 m/s and then speeds up to 23 m/s in 7 seconds. What is the squirrel’s acceleration? Round to the hundredths place. Enter numbers only.

Learn how to calculate the acceleration of a squirrel water skiing behind a boat that speeds up from 8 m/s to 23 m/s in 7 seconds. This problem involves core kinematic concepts, including velocity and acceleration, and uses the formula a = (v_f - v_i) / t. Ideal for students in Grades 8-10.

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