Math Problem Statement

4! (mod 5)

Solution

To compute 4!mod54! \mod 5, follow these steps:

  1. Calculate 4!4!: 4!=4×3×2×1=244! = 4 \times 3 \times 2 \times 1 = 24

  2. Reduce 24mod524 \mod 5: Divide 2424 by 55 and find the remainder: 24÷5=4 remainder 424 \div 5 = 4 \text{ remainder } 4

    Thus, 244(mod5)24 \equiv 4 \pmod{5}

Final Answer:

4!mod5=44! \mod 5 = 4

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Related Questions:

  1. How do you calculate factorials for larger numbers modulo another number?
  2. Why is modular arithmetic important in number theory?
  3. What is the relationship between factorials and prime moduli?
  4. How can modular arithmetic be used in cryptography?
  5. What are the properties of factorials under modular arithmetic?

Tip:

For modular arithmetic, you can simplify intermediate results during calculations to avoid working with large numbers.

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Math Problem Analysis

Mathematical Concepts

Factorials
Modular Arithmetic
Number Theory

Formulas

n! = n × (n-1) × ... × 1
a ≡ b (mod m) if (a - b) is divisible by m

Theorems

Basic Properties of Modular Arithmetic

Suitable Grade Level

Grades 8-10