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The problem involves increasing the initial amount of water by 13%.

Here’s the solution:

- The initial amount of water is 500 mL.
- Georgia increases the amount by 13%, so we calculate 13% of 500 mL:

\[
\text{Increase} = 500 \times \frac{13}{100} = 500 \times 0.13 = 65 \, \text{mL}.
\]

- Now, add the increase to the initial amount of water:

\[
\text{New amount of water} = 500 + 65 = 565 \, \text{mL}.
\]

So, after the increase, the jug contains **565 mL** of water.

Would you like more details or have any questions?

Here are some related questions:
1. What would happen if the water was increased by 25% instead of 13%?
2. How much water would remain if 13% was removed instead of added?
3. What is 13% of 750 mL of water?
4. If the jug originally had 600 mL, how much water would it have after a 13% increase?
5. How would the result change if the water increased by 15%?

**Tip**: When dealing with percentages, always multiply the original value by the percentage expressed as a decimal (e.g., 13% = 0.13).

A jug contained 500 mL of water. Georgia then increased the amount of water in the jug by 13%. How much water was in the jug after the increase? Give your answer in millilitres (mL).

Learn how to calculate a 13% increase in water volume starting with 500 mL. Follow this step-by-step guide to find the new amount, which totals 565 mL after the increase. Ideal for students in Grades 6-8.

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