Math Problem Statement

firm will break even​ (no profit and no​ loss) as long as revenue just equals cost. The value of x​ (the number of items produced and​ sold) where

Upper C left parenthesis x right parenthesis equals Upper R left parenthesis x right parenthesisC(x)=R(x)

is called the​ break-even point. Assume that the below table can be expressed as a linear function.

Find ​(a) the cost​ function, ​(b) the revenue​ function, and ​(c) the profit function.

​(d) Find the​ break-even point and decide whether the product should be​ produced, given the restrictions on sales.

Fixed cost

Variable cost

Price of item

​$300300

​$2020

​$3030

According to the​ restriction, no more than

2121

units can be sold.

Question content area bottom

Part 1

​(a) The cost function is

​C(x)equals=300 plus 20 x300+20x.

​(Simplify your​ answer.)

Part 2

​(​b)

The revenue function is

​R(x)equals=30 x30x.

​(Simplify your​ answer.)

Part 3

​(c) The profit function is

​P(x)equals=enter your response here.

​(Simplify your​ answer.)

Solution

Let's go step by step and fill in the missing parts based on the given information.

Given:

  • Fixed cost = $300
  • Variable cost per item = $20
  • Price of item = $30
  • Maximum units that can be sold = 21 units

Part 1: Cost Function

The cost function C(x)C(x) is the total cost of producing xx items, which includes both the fixed cost and the variable cost.

C(x)=Fixed Cost+(Variable Cost×x)C(x) = \text{Fixed Cost} + (\text{Variable Cost} \times x) C(x)=300+20xC(x) = 300 + 20x

So, the cost function is: C(x)=300+20xC(x) = 300 + 20x

Part 2: Revenue Function

The revenue function R(x)R(x) represents the total revenue obtained from selling xx items, which is the price per item times the number of items sold.

R(x)=Price per item×xR(x) = \text{Price per item} \times x R(x)=30xR(x) = 30x

So, the revenue function is: R(x)=30xR(x) = 30x

Part 3: Profit Function

The profit function P(x)P(x) is the difference between the revenue and the cost:

P(x)=R(x)C(x)P(x) = R(x) - C(x) Substituting the values for R(x)R(x) and C(x)C(x):

P(x)=30x(300+20x)P(x) = 30x - (300 + 20x) Simplifying:

P(x)=30x30020xP(x) = 30x - 300 - 20x P(x)=10x300P(x) = 10x - 300

So, the profit function is: P(x)=10x300P(x) = 10x - 300

Part 4: Break-even Point

The break-even point occurs when revenue equals cost, i.e., R(x)=C(x)R(x) = C(x).

30x=300+20x30x = 300 + 20x Solving for xx:

30x20x=30030x - 20x = 300 10x=30010x = 300 x=30010=30x = \frac{300}{10} = 30

Thus, the break-even point is at 30 units. However, since no more than 21 units can be sold according to the restrictions, the product should not be produced as it is impossible to reach the break-even point.


Let me know if you need further details or have any questions!

Here are five related questions to consider:

  1. What is the significance of the break-even point in business analysis?
  2. How does changing the price per item affect the revenue and profit functions?
  3. If the fixed costs were reduced, how would it impact the break-even point?
  4. How would increasing the maximum number of units sold to 40 affect the decision to produce the product?
  5. What happens if the variable cost per item increases?

Tip: Always ensure that the break-even point is achievable given production or sales constraints before starting a project.

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Math Problem Analysis

Mathematical Concepts

Linear Functions
Break-even Analysis
Revenue and Cost Functions

Formulas

Cost function: C(x) = Fixed cost + (Variable cost × x)
Revenue function: R(x) = Price per item × x
Profit function: P(x) = R(x) - C(x)
Break-even point: R(x) = C(x)

Theorems

Linear function equation solving
Break-even point theorem

Suitable Grade Level

Grades 9-12