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The question reads:

**"The mass of a box and 3 similar books is 2700 g. The mass of the same box and 5 similar books is 4300 g. Find the mass of each book."**

Let's define:
- \( B \) as the mass of the box,
- \( m \) as the mass of one book.

We have two conditions:

1. The mass of the box and 3 books:  
   \[
   B + 3m = 2700 \, \text{g}
   \]

2. The mass of the box and 5 books:  
   \[
   B + 5m = 4300 \, \text{g}
   \]

### Solving the system of equations:
- Subtract the first equation from the second to eliminate \( B \):

\[
(B + 5m) - (B + 3m) = 4300 - 2700
\]
\[
2m = 1600
\]
\[
m = \frac{1600}{2} = 800 \, \text{g}
\]

Thus, the mass of each book is **800 grams**.

### To find the mass of the box \( B \):
Substitute \( m = 800 \) g into the first equation:
\[
B + 3(800) = 2700
\]
\[
B + 2400 = 2700
\]
\[
B = 2700 - 2400 = 300 \, \text{g}
\]

So, the mass of the box is **300 grams**.

Would you like more details on any step? Here are a few related questions for practice:

1. What would be the mass of 10 books and the box combined?
2. If the mass of the box were doubled, how would the total mass change?
3. Can you generalize a formula for the mass of \( n \) books and the box?
4. How would the system of equations change if you had 7 books instead of 5?
5. What happens to the total mass if each book weighed 50 grams less?

**Tip:** In problems with systems of equations, eliminating variables step-by-step makes solving more efficient.

The mass of a box and 3 similar books is 2700 g. The mass of the same box and 5 similar books is 4300 g. Find the mass of each book.

Learn how to find the mass of a book using a system of equations based on the total mass of a box and books. Suitable for students in Grades 6-8, this problem teaches algebraic techniques and elimination method.

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