Math Problem Statement

The given table shows the number of books printed by a publication house in five months. Answer the following questions based on the table: (i) How many more books were printed in March and May together than in January and February together? (ii) Find the fraction of the number of books printed in April to the number of books printed in February. (iii) If the cost of printing each book is ₹125, find the total cost of all the books printed in January and March together.

Solution

Let's analyze and solve the problem step by step.


Interpretation of the Table

The table shows the number of books printed in thousands over five months. Let's convert the tallies into numerical values:

  • January: 15,00015,000 (15 tallies)
  • February: 13,00013,000 (13 tallies)
  • March: 12,00012,000 (12 tallies)
  • April: 16,00016,000 (16 tallies)
  • May: 14,00014,000 (14 tallies)

Questions

(i) How many more books were printed in March and May together than in January and February together?

  1. Books in March and May together:
    12,000+14,000=26,00012,000 + 14,000 = 26,000

  2. Books in January and February together:
    15,000+13,000=28,00015,000 + 13,000 = 28,000

  3. Difference:
    26,00028,000=2,00026,000 - 28,000 = -2,000

Thus, March and May together printed 2,000 fewer books than January and February.\text{March and May together printed 2,000 fewer books than January and February.}


(ii) Find the fraction of the number of books printed in April to the number of books printed in February.

  1. Books in April: 16,00016,000
    Books in February: 13,00013,000

  2. Fraction:
    Fraction=16,00013,000=1613\text{Fraction} = \frac{16,000}{13,000} = \frac{16}{13}


(iii) If the cost of printing each book is ₹125, find the total cost of all the books printed in January and March together.

  1. Books in January and March together:
    15,000+12,000=27,00015,000 + 12,000 = 27,000

  2. Total cost:
    Total cost=27,000×125=3,375,000\text{Total cost} = 27,000 \times 125 = ₹3,375,000


Answer Key

  1. (i): 2,000-2,000
  2. (ii): 1613\frac{16}{13}
  3. (iii): ₹3,375,000

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Math Problem Analysis

Mathematical Concepts

Arithmetic operations
Fraction simplification
Cost calculation

Formulas

Addition: Total = Value1 + Value2
Subtraction: Difference = Value1 - Value2
Fraction: Fraction = Numerator / Denominator
Cost calculation: Total cost = Number of items × Cost per item

Theorems

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Suitable Grade Level

Grade 6-8