Math Problem Statement

Question content area top Part 1 Eighty dash five

percent of adults want to live to age 100. You randomly select five adults and ask them whether they want to live to age 100. The random variable represents the number of adults who want to live to age 100. Complete parts​ (a) through​ (c) below. Question content area bottom Part 1 ​(a) Construct a binomial distribution. x

​P(x) 0

enter your response here 1

enter your response here 2

enter your response here 3

enter your response here 4

enter your response here 5

enter your response here ​(Round to five decimal places as​ needed.)

Solution

To construct the binomial distribution, we need to use the following formula for the probability of exactly xx successes in nn trials:

P(x)=(nx)px(1p)nxP(x) = \binom{n}{x} p^x (1 - p)^{n - x}

Where:

  • nn = 5 (the number of trials, which is the number of adults selected),
  • pp = 0.80 (the probability that an adult wants to live to age 100),
  • 1p1 - p = 0.20 (the probability that an adult does not want to live to age 100),
  • xx is the number of adults who want to live to age 100.

For each value of xx, we'll calculate P(x)P(x) using the formula.

Step 1: Calculate each P(x)P(x) for x=0,1,2,3,4,5x = 0, 1, 2, 3, 4, 5.

For x=0x = 0:

P(0)=(50)(0.80)0(0.20)5=1×1×0.00032=0.00032P(0) = \binom{5}{0} (0.80)^0 (0.20)^5 = 1 \times 1 \times 0.00032 = 0.00032

For x=1x = 1:

P(1)=(51)(0.80)1(0.20)4=5×0.80×0.0016=0.0064P(1) = \binom{5}{1} (0.80)^1 (0.20)^4 = 5 \times 0.80 \times 0.0016 = 0.0064

For x=2x = 2:

P(2)=(52)(0.80)2(0.20)3=10×0.64×0.008=0.0512P(2) = \binom{5}{2} (0.80)^2 (0.20)^3 = 10 \times 0.64 \times 0.008 = 0.0512

For x=3x = 3:

P(3)=(53)(0.80)3(0.20)2=10×0.512×0.04=0.2048P(3) = \binom{5}{3} (0.80)^3 (0.20)^2 = 10 \times 0.512 \times 0.04 = 0.2048

For x=4x = 4:

P(4)=(54)(0.80)4(0.20)1=5×0.4096×0.20=0.4096P(4) = \binom{5}{4} (0.80)^4 (0.20)^1 = 5 \times 0.4096 \times 0.20 = 0.4096

For x=5x = 5:

P(5)=(55)(0.80)5(0.20)0=1×0.32768×1=0.32768P(5) = \binom{5}{5} (0.80)^5 (0.20)^0 = 1 \times 0.32768 \times 1 = 0.32768

Step 2: Fill out the table

xxP(x)P(x)
00.00032
10.00640
20.05120
30.20480
40.40960
50.32768

Answer:

  • P(0)=0.00032P(0) = 0.00032
  • P(1)=0.00640P(1) = 0.00640
  • P(2)=0.05120P(2) = 0.05120
  • P(3)=0.20480P(3) = 0.20480
  • P(4)=0.40960P(4) = 0.40960
  • P(5)=0.32768P(5) = 0.32768

Would you like any further explanation or details on any of the steps?


Here are 5 related questions to expand the topic:

  1. How do you calculate the binomial coefficient (nx)\binom{n}{x}?
  2. How would the probabilities change if the percentage of adults who want to live to age 100 were 90% instead of 80%?
  3. How do you find the mean and standard deviation for a binomial distribution?
  4. What happens to the binomial distribution if the number of adults surveyed (n) increases to 10?
  5. How can you use a cumulative binomial distribution table for this problem?

Tip: For more complex binomial distributions, consider using a calculator or software to quickly compute the probabilities!

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Math Problem Analysis

Mathematical Concepts

Probability
Binomial Distribution
Combinatorics

Formulas

P(x) = C(n, x) * p^x * (1 - p)^(n - x)
C(n, x) = n! / (x! * (n - x)!)

Theorems

Binomial Theorem
Fundamental Principle of Counting

Suitable Grade Level

Grades 10-12