The expression in the image appears to be a binomial coefficient, which is typically written as $\binom{a}{b}$, denoting "a choose b." In this case, it looks like:

$\binom{3}{2}$

This is interpreted as the number of ways to choose 2 elements from a set of 3, which is calculated using the combination formula:

$\binom{n}{k} = \frac{n!}{k!(n-k)!}$

So, for $\binom{3}{2}$:

$\binom{3}{2} = \frac{3!}{2!(3-2)!} = \frac{3 \times 2 \times 1}{2 \times 1 \times 1} = \frac{6}{2} = 3$

Thus, $\binom{3}{2} = 3$.

Would you like more details on this topic or any additional clarifications?

Here are five related questions:

1. How does the combination formula differ from the permutation formula?
2. What is the value of $\binom{5}{3}$?
3. How do you calculate factorial values like $6!$ or $7!$?
4. What is the difference between combinations and arrangements?
5. How would you use combinations to solve a probability problem?

Tip: In combinatorics, order does not matter for combinations, but it does for permutations.