Math Problem Statement
Let U = { p in p_4(R) : p’’(6)=0. Find a basis of U
Solution
Given , we need to find a basis for . Here's the step-by-step breakdown:
Step 1: General form of a polynomial in
A polynomial in is of degree at most 4, so we can express a general element of as: where are constants.
Step 2: Second derivative of
To impose the condition , we first compute the second derivative of .
First derivative:
Second derivative:
Step 3: Apply the condition
Substitute into the second derivative and set it equal to 0: Simplifying: Dividing the entire equation by 2: Thus, the condition that must hold for is:
Step 4: Express in terms of free variables
From the condition above, we can express in terms of and . So, the polynomial becomes:
Step 5: Construct a basis
The free variables are , so we can generate a basis by assigning one of these variables to 1 and the others to 0 in turn:
-
Set , , , :
-
Set , , , :
-
Set , , , :
-
Set , , , :
Step 6: Final basis
Thus, a basis for is:
Would you like more details on any part of the solution or have any questions?
Here are 5 related questions to consider:
- What is the dimension of the space ?
- How would the basis change if the condition was instead of ?
- What does it mean geometrically for a polynomial to satisfy ?
- How would you find a basis if the degree of the polynomial was higher, say ?
- How can this method be extended to polynomials over other fields?
Tip: When solving for a subspace of polynomials, always focus on the conditions imposed on the derivatives or values to reduce the degrees of freedom.
Ask a new question for Free
By Image
Drop file here or Click Here to upload
Math Problem Analysis
Mathematical Concepts
Polynomials
Linear Algebra
Basis of a Vector Space
Differentiation
Formulas
General polynomial of degree 4: p(x) = ax^4 + bx^3 + cx^2 + dx + e
First derivative: p'(x) = 4ax^3 + 3bx^2 + 2cx + d
Second derivative: p''(x) = 12ax^2 + 6bx + 2c
Condition for second derivative at x=6: 216a + 18b + c = 0
Theorems
Basis Theorem: A basis is a set of linearly independent vectors that span the space.
Suitable Grade Level
Undergraduate Mathematics
Related Recommendation
Basis for the Polynomial Vector Space p(x) in R4[X] with Conditions p(-1) = 0 and p''(-1) = 0
Find Basis B of Subspace U with Coefficient x⁴ = 10
Find Basis and Dimension of Subspaces in P3(R) with Specific Conditions
Basis for Subspace U and Orthogonal Complement U⊥ in P2(R)
Basis and Dimension of the Space Generated by Polynomials x^3+3x^2-x+4 and 2x^3+x^2-7x-7