https://file.aiquickdraw.com/mathbot/file/1726798621716eupyvs4b.jpg

The problem in the image is written in Indonesian and translates to:

"a. The average ratio of the change in distance \(s\) with respect to time \(t\) from \(t = 1\) to \(t = 1.3\)"

This question is likely asking for the calculation of the average velocity over the given time interval, as the "ratio of the change in distance with respect to time" suggests.

To compute the average velocity:

\[
\text{Average Velocity} = \frac{\Delta s}{\Delta t}
\]

Where:
- \(\Delta s\) is the change in distance \(s\),
- \(\Delta t = t_2 - t_1\) is the change in time, with \(t_1 = 1\) and \(t_2 = 1.3\).

If you have a function for distance \(s(t)\) over time, we can substitute these values to calculate the average velocity. Would you like to provide the function or further clarify? Let me know if you'd like more details or have any specific questions.

Here are some follow-up questions related to this concept:

1. What is the formula for average velocity in terms of distance and time?
2. How does the change in distance (\(\Delta s\)) affect the average velocity calculation?
3. Can the average velocity be negative? Under what conditions?
4. How would the formula change if the velocity is not constant?
5. How can instantaneous velocity be derived from the given information?

**Tip:** In kinematics, the average velocity over a time interval gives a measure of the total distance covered divided by the time taken, while instantaneous velocity is the velocity at a specific moment in time.

Rata-rata perbandingan perubahan jarak s terhadap waktu t dari t = 1 sampai dengan t = 1,3.

Learn how to calculate the average velocity over a time interval from t = 1 to t = 1.3 by using the formula Average Velocity = Δs / Δt. Understand kinematic concepts and how the change in distance over time affects the velocity.

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