Math Problem Statement
Solution
Let's walk through the questions step by step from the image provided:
(a) Find the average rate of change of on the interval .
The average rate of change of a function on the interval is calculated by: From the graph:
- appears to be 800.
- is approximately 500.
Now we calculate: The correct answer is , and this was marked as correct.
(b) Identify an interval on which the average rate of change of is 0.
The average rate of change is 0 if the function does not change over the interval (i.e., it's constant). From the graph, the function is flat between and , meaning the slope is 0 in that region.
The correct interval is , which was selected and marked correct.
(c) Compute the following:
From the graph:
- appears to be approximately 500.
- is approximately 500.
Thus: This is marked as incorrect in the problem, but the calculation is actually correct. The value is .
What does this value represent geometrically?
Since the rate of change is 0, it means that the slope of the line segment from to is 0. The correct interpretation geometrically is that it represents "the slope of the line segment from to ." This was marked as correct.
Do you have any questions or need further details on any of these solutions?
5 related questions:
- How is the average rate of change different from the instantaneous rate of change?
- What does a zero average rate of change imply about the function over the interval?
- How can we visually identify where the average rate of change is zero on a graph?
- What role do the endpoints of an interval play in determining the average rate of change?
- How would you compute the instantaneous rate of change from a graph?
Tip:
When calculating the average rate of change, always ensure you have accurately read the values of and from the graph or function before performing the computation.
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Math Problem Analysis
Mathematical Concepts
Rate of Change
Intervals
Graph Interpretation
Slope
Formulas
Average rate of change formula: (f(b) - f(a)) / (b - a)
Theorems
The concept of slope for linear segments on a graph
Suitable Grade Level
Grades 9-12
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