Math Problem Statement

Below, C(x) is the cost, in dollars, to produce x items in a factory. Find the following: (a) The average cost at the production level 1350, (b) The production level that will minimize the average cost, and (c) The minimal average cost.

Solution

Let's analyze and solve the given problem. The cost function provided is:

C(x)=220+700x+x2C(x) = 220 + 700x + x^2

where C(x)C(x) represents the total cost to produce xx items.

The questions require us to:

a) Find the average cost at the production level x=1350x = 1350.

The average cost function is given by:

Average Cost=C(x)x=220+700x+x2x\text{Average Cost} = \frac{C(x)}{x} = \frac{220 + 700x + x^2}{x}

For x=1350x = 1350, substitute this value into the equation to compute the average cost.

b) Find the production level xx that minimizes the average cost.

This requires finding the critical points of the average cost function, which involves taking its derivative, setting it equal to zero, and solving for xx.

c) Find the minimal average cost.

Substitute the xx-value from part (b) into the average cost function to compute the minimal average cost.

Would you like a detailed solution for each part now?

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Algebra
Optimization
Derivatives

Formulas

C(x) = 220 + 700x + x^2
Average Cost = C(x)/x
To minimize a function, find the derivative and set it equal to zero

Theorems

Derivative to find minima/maxima
Quadratic functions

Suitable Grade Level

Grades 11-12