Math Problem Statement

An astronaut is rotated in a horizontal centrifuge at a radius of 5.00 m. (a) What is the astronaut's speed if the centripetal acceleration has a magnitude of 6.90g? (b) How many revolutions per minute are required to produce this acceleration? (c) What is the period of the motion?

Solution

The problem you shared is about circular motion, particularly focusing on an astronaut in a centrifuge. Let's go step by step through the questions:

Given:

  • Radius r=5.00mr = 5.00 \, \text{m}
  • Centripetal acceleration ac=6.90ga_c = 6.90g, where g9.81m/s2g \approx 9.81 \, \text{m/s}^2.

So, ac=6.90×9.81=67.689m/s2a_c = 6.90 \times 9.81 = 67.689 \, \text{m/s}^2.

(a) What is the astronaut's speed?

The centripetal acceleration is related to the speed vv by the formula: ac=v2ra_c = \frac{v^2}{r} Solving for vv: v=ac×r=67.689×5.0018.41m/sv = \sqrt{a_c \times r} = \sqrt{67.689 \times 5.00} \approx 18.41 \, \text{m/s}

(b) How many revolutions per minute are required to produce this acceleration?

First, we need to find the angular velocity ω\omega in radians per second. The formula linking speed to angular velocity is: v=ωrorω=vrv = \omega r \quad \text{or} \quad \omega = \frac{v}{r} Substituting v=18.41m/sv = 18.41 \, \text{m/s} and r=5.00mr = 5.00 \, \text{m}: ω=18.415.003.682rad/s\omega = \frac{18.41}{5.00} \approx 3.682 \, \text{rad/s} Now, to find the revolutions per second (rps), we convert from radians per second to revolutions per second using the fact that 2πradians=1revolution2\pi \, \text{radians} = 1 \, \text{revolution}: rps=ω2π=3.6822π0.586rps\text{rps} = \frac{\omega}{2\pi} = \frac{3.682}{2\pi} \approx 0.586 \, \text{rps} Finally, to find revolutions per minute (rpm): rpm=0.586×6035.17rpm\text{rpm} = 0.586 \times 60 \approx 35.17 \, \text{rpm}

(c) What is the period of the motion?

The period TT is the time it takes to complete one full revolution. It is related to the frequency by: T=1fT = \frac{1}{f} where ff is the frequency in revolutions per second. From part (b), we found f=0.586rpsf = 0.586 \, \text{rps}, so: T=10.5861.71secondsT = \frac{1}{0.586} \approx 1.71 \, \text{seconds}


Let me know if you'd like any more details on the solution, or if you have any questions!

Follow-up questions:

  1. How does changing the radius affect the speed required to maintain the same centripetal acceleration?
  2. What is the relationship between angular velocity and centripetal acceleration?
  3. How would the number of revolutions per minute change if the astronaut's centripetal acceleration was doubled?
  4. What would happen to the period if the radius was halved?
  5. How is centripetal force related to mass in this scenario?

Tip:

In circular motion, increasing the radius while keeping centripetal acceleration constant will reduce the speed needed to maintain that acceleration.

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Math Problem Analysis

Mathematical Concepts

Circular Motion
Centripetal Acceleration
Angular Velocity
Period of Motion
Revolutions per Minute

Formulas

Centripetal acceleration formula: a_c = v^2 / r
Angular velocity formula: v = ωr
Revolutions per second: ω / (2π)
Period formula: T = 1 / f

Theorems

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Suitable Grade Level

Grades 10-12 (High School Physics)