Math Problem Statement

Ashley plants a tree 45 cm tall. It grows by 10 cm each year. As a reward for looking after his tree, Ashley's parents give him the height of the tree in pounds each year. Find the amount Ashley gets in the 9th year. Write down and simplify a formula for the total amount of money after n years. Use @ for ^2. How many years will it take Ashley to make a total of $525?

Solution

Let's go through the problem step by step.

Problem Breakdown:

  1. Initial Tree Height: 45 cm
  2. Growth per Year: 10 cm

1. Finding the Amount Ashley Gets in the 9th Year:

  • Height in 9th Year: The tree's height increases by 10 cm each year. Therefore, after 9 years, the height will be: Height in 9th year=45+10×(91)=45+80=125 cm\text{Height in 9th year} = 45 + 10 \times (9-1) = 45 + 80 = 125 \text{ cm}
  • Ashley's parents give him the height of the tree in pounds as a reward. So, the amount Ashley gets in the 9th year is $125.

2. Formula for the Total Amount after nn Years:

  • The height of the tree in the nnth year is: Height in nth year=45+10×(n1)\text{Height in } n \text{th year} = 45 + 10 \times (n-1)
  • The total amount of money after nn years will be the sum of the tree heights for each year up to the nnth year. This sum can be represented as: Total Amount after n years=i=1n(45+10×(i1))\text{Total Amount after } n \text{ years} = \sum_{i=1}^{n} \left( 45 + 10 \times (i-1) \right)
  • Simplifying the sum: Total Amount after n years=n×45+10×i=1n(i1)\text{Total Amount after } n \text{ years} = n \times 45 + 10 \times \sum_{i=1}^{n} (i-1) The sum i=1n(i1)\sum_{i=1}^{n} (i-1) is a sum of the first n1n-1 natural numbers, which is given by: i=1n(i1)=(n1)n2\sum_{i=1}^{n} (i-1) = \frac{(n-1)n}{2} So the total amount simplifies to: Total Amount after n years=n×45+5×(n1)×n\text{Total Amount after } n \text{ years} = n \times 45 + 5 \times (n-1) \times n =45n+5n25n=5n2+40n= 45n + 5n^2 - 5n = 5n^2 + 40n The formula for the total amount after nn years is: An=5n2+40nA_n = 5n^2 + 40n

3. Finding the Number of Years to Make a Total of $525:

  • We need to solve the quadratic equation: 5n2+40n=5255n^2 + 40n = 525 Simplifying: n2+8n105=0n^2 + 8n - 105 = 0 Solving this quadratic equation using the quadratic formula: n=8±82+4×1×1052×1n = \frac{-8 \pm \sqrt{8^2 + 4 \times 1 \times 105}}{2 \times 1} n=8±64+4202=8±4842=8±222n = \frac{-8 \pm \sqrt{64 + 420}}{2} = \frac{-8 \pm \sqrt{484}}{2} = \frac{-8 \pm 22}{2} The two possible solutions are: n=142=7andn=302=15n = \frac{14}{2} = 7 \quad \text{and} \quad n = \frac{-30}{2} = -15 Since the number of years cannot be negative, n=7n = 7.

Therefore, it will take Ashley 7 years to make a total of $525.


Would you like more details or have any other questions?

Follow-up Questions:

  1. What will be the total amount Ashley receives in the 12th year?
  2. How much will Ashley receive in the 5th year?
  3. What is the total amount Ashley receives in the first 3 years?
  4. How does the amount Ashley receives change with each passing year?
  5. Can you verify the quadratic formula used to find the number of years?

Tip:

For problems involving sequences, recognizing whether they are arithmetic or geometric can help simplify calculations significantly.

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Math Problem Analysis

Mathematical Concepts

Arithmetic Sequences
Algebra
Quadratic Equations

Formulas

Height in nth year: Height_n = 45 + 10 * (n - 1)
Total amount after n years: A_n = 5n^2 + 40n
Quadratic equation formula: n^2 + 8n - 105 = 0

Theorems

Quadratic formula

Suitable Grade Level

Grades 7-9