Math Problem Statement

help with "carry out procedure" section

Help with 'carry out procedure' section.

Solution

In the "Carry Out Procedure" section, you are given a sequence, and the instructions are as follows:

  1. Given the arithmetic sequence an=2+5na_n = 2 + 5n:
    • a) Find a1a_1: This is the first term in the sequence, which you can calculate by plugging n=1n = 1 into the formula.
    • b) Identify the common difference, dd: In an arithmetic sequence, the common difference is the constant difference between consecutive terms. This is often represented by the coefficient of nn in the general formula.

Let's solve these steps:

Step-by-Step Solution

Part (a): Find a1a_1

The formula for the arithmetic sequence is: an=2+5na_n = 2 + 5n To find a1a_1, substitute n=1n = 1: a1=2+5(1)=2+5=7a_1 = 2 + 5(1) = 2 + 5 = 7 So, a1=7a_1 = 7.

Part (b): Identify the common difference dd

In the given sequence formula an=2+5na_n = 2 + 5n, the term 55 represents the common difference because it is the value added each time nn increases by 1.

Thus, d=5d = 5.

Final Answers

  • (a) a1=7a_1 = 7
  • (b) The common difference d=5d = 5

Would you like more details on this section, or do you need help with other parts of the worksheet?


Additional Practice Questions

  1. If an=2+5na_n = 2 + 5n, what is the 10th term, a10a_{10}?
  2. For an arithmetic sequence with a1=3a_1 = 3 and d=4d = 4, write the explicit formula for ana_n.
  3. How would you find the sum of the first 15 terms in an arithmetic sequence where a1=7a_1 = 7 and d=5d = 5?
  4. If the common difference dd were changed to 33, what would the new sequence formula look like?
  5. How can you determine if a sequence is arithmetic by looking at its formula?

Tip:

In an arithmetic sequence, the common difference can be found by subtracting any two consecutive terms.

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Math Problem Analysis

Mathematical Concepts

Arithmetic Sequences
Linear Patterns

Formulas

Arithmetic sequence formula: a_n = a_1 + (n - 1)d

Theorems

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Suitable Grade Level

High School - Precalculus