Math Problem Statement

Consider the sequence: 2, 10, 18, 26, 34, 42, 50, ... a) Find the nth term of the sequence. b) Find the 200th term. c) Which term of this sequence has the value 234? Show full working. d) Show that 139 is not a term in the sequence.

Solution

Solution:

a) Find the nth term of the sequence.

The given sequence is: 2,10,18,26,34,42,50,2, 10, 18, 26, 34, 42, 50, \ldots.

  1. Identify the difference between consecutive terms: 102=8,  1810=8,  2618=8,  and so on.10 - 2 = 8, \; 18 - 10 = 8, \; 26 - 18 = 8, \; \text{and so on.} The sequence has a common difference of d=8d = 8.

  2. General form of an arithmetic sequence: The formula for the nn-th term of an arithmetic sequence is: an=a1+(n1)da_n = a_1 + (n-1)d where a1a_1 is the first term and dd is the common difference.

  3. Substitute a1=2a_1 = 2 and d=8d = 8: an=2+(n1)8a_n = 2 + (n-1) \cdot 8 Simplify: an=2+8n8=8n6a_n = 2 + 8n - 8 = 8n - 6 So, the nn-th term is: an=8n6a_n = 8n - 6


b) Find the 200th term.

Using the formula an=8n6a_n = 8n - 6: a200=82006=16006=1594a_{200} = 8 \cdot 200 - 6 = 1600 - 6 = 1594 Thus, the 200th term is: 1594\boxed{1594}


c) Which term of this sequence has the value 234?

We need to solve for nn when an=234a_n = 234. Using the formula an=8n6a_n = 8n - 6: 234=8n6234 = 8n - 6 Add 6 to both sides: 240=8n240 = 8n Divide by 8: n=30n = 30 Thus, the 30th term of the sequence is: 234\boxed{234}


d) Show that 139 is not a term in the sequence.

For 139 to be a term, it must satisfy an=8n6a_n = 8n - 6, where nn is an integer. Solve for nn: 139=8n6139 = 8n - 6 Add 6 to both sides: 145=8n145 = 8n Divide by 8: n=1458=18.125n = \frac{145}{8} = 18.125 Since nn is not an integer, 139 is not a term in the sequence. Therefore: 139 is not in the sequence.\boxed{139 \text{ is not in the sequence.}}


Summary of Results:

  • a) an=8n6a_n = 8n - 6
  • b) a200=1594a_{200} = 1594
  • c) 234234 is the 3030-th term.
  • d) 139139 is not a term in the sequence.

Let me know if you’d like further details or clarifications!


Related Questions:

  1. What is the sum of the first 50 terms of this sequence?
  2. How would the sequence change if the first term were 44 and the difference were 1010?
  3. Can you derive a formula for the sum of the first nn terms of this sequence?
  4. What is the general method to check if a number belongs to an arithmetic sequence?
  5. If the sequence were geometric, what would the formula for the nn-th term look like?

Tip:

Always confirm that the value of nn is an integer when determining whether a number belongs to an arithmetic sequence.

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Math Problem Analysis

Mathematical Concepts

Arithmetic Sequences
Algebra

Formulas

nth term of an arithmetic sequence: a_n = a_1 + (n-1)d

Theorems

Properties of arithmetic sequences

Suitable Grade Level

Grades 9-12