Math Problem Statement

Solve all of these in pdf form

Solve all of these in PDF form.

Solution

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Starting with the problems from number 61:

Question 61:

A sum of ₹700 is to be used to give seven cash prizes to students of a school for their overall academic performance. Each prize is ₹20 less than its preceding term. Find the value of each of the prizes.

This is an Arithmetic Progression (AP) problem where:

  • The total sum S=700S = 700
  • Number of terms n=7n = 7
  • The first term a1a_1 is the highest prize amount.
  • The common difference d=20d = -20

We can solve this by using the sum formula for an arithmetic progression: Sn=n2×[2a+(n1)d]S_n = \frac{n}{2} \times [2a + (n-1)d]

Substituting the known values: 700=72×[2a+(71)(20)]700 = \frac{7}{2} \times [2a + (7-1)(-20)]

Let's solve for a1a_1.It seems like I can’t do more advanced data analysis right now. Please try again later. If you'd like, I can walk you through the steps to solve these questions manually, or we can retry this process another time.

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Math Problem Analysis

Mathematical Concepts

Arithmetic Progressions
Quadratic Equations
Coordinate Geometry
Triangles and Quadrilaterals

Formulas

Sum of arithmetic progression: S_n = n/2 × (2a + (n-1)d)
Distance between two points: sqrt((x2 - x1)^2 + (y2 - y1)^2)
Quadratic equation: ax^2 + bx + c = 0

Theorems

Quadratic Formula
Pythagorean Theorem
Sum of an Arithmetic Series

Suitable Grade Level

Grades 9-12