https://file.aiquickdraw.com/mathbot/file/1727220245451f33ohtjp.jpg

Let's break down the problem:

1. **Shape Dimensions:**
   - The figure is a circle inscribed in a square. Both the circle and the square have a side length (or diameter in the case of the circle) of 8 units.

2. **Shaded Area:**
   - The area of the shaded region is the difference between the area of the square and the area of the circle.

3. **Formulae:**
   - Area of the square: \( A_{\text{square}} = \text{side}^2 = 8^2 = 64 \, \text{square units} \).
   - Area of the circle: \( A_{\text{circle}} = \pi r^2 \), where \( r \) is the radius of the circle. Since the diameter of the circle is 8, the radius \( r \) is \( 4 \) units. With \( \pi = 3.14 \):
     \[
     A_{\text{circle}} = 3.14 \times 4^2 = 3.14 \times 16 = 50.24 \, \text{square units}.
     \]

4. **Shaded Area Calculation:**
   \[
   A_{\text{shaded}} = A_{\text{square}} - A_{\text{circle}} = 64 - 50.24 = 13.76 \, \text{square units}.
   \]

Rounding 13.76 to the nearest tenth gives **13.8**.

Thus, the correct answer is **B) 13.8**.

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Do you want more details, or have any further questions?

Here are 5 related questions for practice:
1. What would be the area of the circle if the diameter was 10 units?
2. How would the shaded area change if the square had a side length of 10 units instead of 8?
3. How does the area of a square change if the side length is doubled?
4. If the circle's diameter is halved, what happens to its area?
5. What is the circumference of the circle given in this problem?

**Tip:** When calculating areas of composite figures, always find the area of each part separately before subtracting!

Find the area of the shaded part in the diagram. The area of a circle is equal to πr², where π = 3.14. Round off the answer to the nearest tenth.

This geometry problem involves calculating the shaded area between an inscribed circle and a square. Key concepts include areas of circles (πr²) and squares (side²). The problem is suitable for middle school students, especially in Grades 6-8.

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