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The image provided contains a problem in polar coordinates related to finding the area enclosed by a single petal of a rose curve described by the equation \( r = \cos(2\theta) \). Let's go through it step-by-step.

### Problem: 
You are asked to find the area enclosed by one petal of the rose curve \( r = \cos(2\theta) \) using a double integral.

### Solution Outline:
1. **Identifying the Region**: 
   From the sketch and the provided description, one petal of the rose curve corresponds to an angular range between \( -\frac{\pi}{4} \leq \theta \leq \frac{\pi}{4} \). The radius \( r \) varies from 0 to \( \cos(2\theta) \), which means the area is described by the polar region:
   \[
   D = \{ (r, \theta) \mid -\frac{\pi}{4} \leq \theta \leq \frac{\pi}{4}, 0 \leq r \leq \cos(2\theta) \}.
   \]

2. **Using

Gunakan integral ganda untuk mencari daerah yang tertutup oleh satu putaran mawar berdaun empat r = cos 2θ.

This problem focuses on calculating the area enclosed by a single petal of the rose curve r = cos(2θ) using double integrals in polar coordinates. The solution involves setting up the integral with proper limits for θ and r, integrating over the specified region, and applying polar area formulas. Suitable for university-level calculus students.

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